how many grams of glucose must be added to 525g of 2.5 percent leg mass glucose solution?and give the furmela?
Another way to express the concentration of a 0.01 percent by weight glucose solution is to say it is a 100 parts per million (ppm) solution. This means there are 100 grams of glucose in every 1 million grams of solution.
Another way to express the concentration of a glucose solution that is 0.01 percent by weight is as 100 parts per million (ppm). This means there are 100 grams of glucose in 1 million grams of solution.
A 30% glucose solution is purely glucose and water, though it is actually impossible to keep other contaminants out of it. To create a 30% solution of glucose, you take a fixed volume of water and add 30% of that value of glucose to the water. The amount of glucose is in grammes. For example, 3g of glucose would be added to 10ml of water.
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 40.0mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?
You need 0,9 glucose.
40.8 grams
Another way to express the concentration of a 0.01 percent by weight glucose solution is to say it is a 100 parts per million (ppm) solution. This means there are 100 grams of glucose in every 1 million grams of solution.
Another way to express the concentration of a glucose solution that is 0.01 percent by weight is as 100 parts per million (ppm). This means there are 100 grams of glucose in 1 million grams of solution.
A 30% glucose solution is purely glucose and water, though it is actually impossible to keep other contaminants out of it. To create a 30% solution of glucose, you take a fixed volume of water and add 30% of that value of glucose to the water. The amount of glucose is in grammes. For example, 3g of glucose would be added to 10ml of water.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
200 grams/1,000 mL x 100= 20%
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
195 grams.
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 40.0mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?
To find the mass of glucose in the solution, we first need to calculate the volume of glucose in the solution. Using the formula m = V x mv, we find that the mass of glucose (m) in 205 mL of a 5.50 mv glucose solution is approximately 11.28 grams.
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.