800 g oxygen are needed.
394.794 grams
89.3
This depends on the compound.
For the reaction 2Hβ + Oβ β 2HβO, we know that the molar ratio of Hβ to Oβ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
A lot
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
800 g oxygen are needed.
530,3 g potassium iodide are needed.
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
To solve this, we will figure out how many grams there are per litre. To do this, we will divide the overall amount of litres 350 grams goes into by 350, so we are dividing 350 by 10,000. This answer is 0.035. We will then multiply 0.035 (how many grams needed for one litre) by 3300, to get how many are needed for that many litres, which gives us 115.5 grams. 115.5 grams are needed for 3300 litres if 250 grams are needed for 10,000 litres.
394.794 grams
About 245 grams.
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.
To calculate the amount of calcium oxide needed to produce 36.0 g of mercury (Hg), we need to first determine the molar ratio between calcium oxide and mercury. The molar ratio can be determined from the balanced chemical equation of the reaction. Once the molar ratio is known, we can use it to find the amount of calcium oxide needed to produce 36.0 g of mercury.
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.