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How many grams of calcium sulfate will be formed if 130 grams of calcium hydroxide reacts with an excess of sulfuric acid?
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What happens when excess of CO2 is passed through lime vessel?
When excess CO2 is passed through a lime vessel, it reacts with the lime (CaO) to form calcium carbonate (CaCO3) through a process called carbonation. This reaction removes the excess CO2 from the system and produces calcium carbonate as a white precipitate.
Why is calcium carbonate used to neutralize acidic water instead of calcium oxide?
Because if you over correct, excess calcium carbonate is all but harmless, whilst excess sodium hydroxide can be corrosive and toxic.
How can you get crystals from the reaction of magnesium and sulphuric acid?
To obtain crystals from the reaction of magnesium and sulfuric acid, you can follow these steps: 1) Mix magnesium ribbon with diluted sulfuric acid in a beaker. 2) Allow the reaction to occur, which will produce hydrogen gas and magnesium sulfate. 3) Filter the mixture to remove any excess magnesium or impurities. 4) Evaporate the filtered solution to allow the magnesium sulfate to crystallize and form crystals.
Where is excess calcium stored when blood calcium levels increase?
Excess calcium is stored in the bones when blood calcium levels increase. This process is regulated by hormones such as calcitonin and parathyroid hormone, which help maintain calcium balance in the body.
What happen when carbon di oxide passed through lime water in excess?
When carbon dioxide is passed through lime water in excess, a white precipitate of calcium carbonate is formed. This is because carbon dioxide reacts with the calcium hydroxide in lime water to form calcium carbonate, which is insoluble and appears as a solid in the solution. This reaction is used as a test for the presence of carbon dioxide gas.
One mole of calcium phosphide on reaction with excess of water gives what?
One mole of calcium phosphide on reaction with excess water produces calcium hydroxide and phosphine gas. This reaction can be represented as Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3.
How excess acidity can be treated using calcium hydroxide?
Excess acidity can be treated using calcium hydroxide, also known as slaked lime, by adding it to the acidic solution. The calcium hydroxide reacts with the hydrogen ions in the solution to form water and calcium ions, which reduces the acidity. This process is known as neutralization and helps to raise the pH of the solution.
Why only magnisium sulphate and calcium sulphate cause hardness of water not sodium sulphate?
Magnesium sulfate and calcium sulfate cause hardness in water because they are slightly soluble in water, leading to the presence of excess ions in the water. Sodium sulfate, on the other hand, is highly soluble and does not produce excess ions that contribute to water hardness.
Is sodium sulfate more soluble at high pH or low pH?
Sodium sulfate is more soluble at high pH because it is a salt of a strong base (sodium hydroxide) and a weak acid (sulfuric acid). At high pH, the excess hydroxide ions can react with the sulfate ions to form more soluble compounds, increasing the solubility of sodium sulfate.
When excess of ammonia is added to aqueous zinc sulfate does the precipitate dissolve?
Yes. The ammonia will form ammonium hydroxide. The ammonium cation (NH4+) will react with SO4^2- to form the soluble salt ammonium sulfate, (NH4)2SO4. According to Le Chatelier's Principle, this will push the reaction to the right, thus forming more ammonium sulfate from the insoluble zinc sulfate.
Aluminum sulfate reacts with ammonium hydroxide to form what?
Aluminum sulfate reacts with ammonium hydroxide to form aluminum hydroxide and ammonium sulfate.
Why was the copper II oxide added in excess to dilute sulfuric acid to form the soluble salt copper II sulphate?
Copper II oxide was added in excess to ensure that all the sulfuric acid reacted, forming water and copper II sulfate. This method helps to avoid any excess sulfuric acid remaining in the solution, ensuring that all copper II oxide reacts completely to form the desired copper II sulfate salt.
When 400.0 g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 1463.0 g of product were obtained What is the percent yield of ammonium sulfate for this reaction?
94.25 - 94.28
How to tranform cupric sulfate to cupric hydroxide?
To transform cupric sulfate to cupric hydroxide, you can mix cupric sulfate (CuSO4) with a base like sodium hydroxide (NaOH) in a reaction vessel. The balanced chemical equation for this reaction is: CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4. This will result in the formation of cupric hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4) as a byproduct.
300 g of ammonia react with 36 moles of sulfuric acid to produce ammonia sulfate how many moles of excess sulfuric acid are left over after the reaction is complete?
26.9 - 27.4
When 300.0 g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 985.0 g of product were obtained What is the percent yield of ammonium sulfate for this reaction?
84.62 - 84.66 or 84.64%.
What is milk of lime?
Milk of lime is a suspension of calcium hydroxide in water, also known as slaked lime. It is commonly used in various industries, such as agriculture and wastewater treatment, for its alkaline properties to neutralize acidity or precipitate impurities.
