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At STP (Standard Temperature and Pressure: 0°C and 1 atm pressure), 1 mole of any gas occupies 22.4 L. Therefore, to find the number of moles of O gas in 10.0 L at STP, we divide 10.0 by 22.4 to get 0.4464 moles. The molar mass of oxygen (O₂) is 32 g/mol, so 0.4464 moles of O₂ gas would be 0.4464 moles * 32 g/mol ≈ 14.3 grams.
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What is the volume of 84.6 grams of helium at stp?
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
How many moles of of hydrogen gas occupy 112L at stp?
Ideal gas equation. PV = nRT ===============
What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
What volume does 0.685 moles of gas occupy at stp?
The volume is approx. 15,35 litres.
What volume (in liters) does 2.895 mole of oxygen occupy at STP?
The volume is 64,8 L.
At STP 32 grams of O2 would occupy the same volume as?
At STP (standard temperature and pressure), 32 grams of O2 would occupy the same volume as 22.4 liters, which is the molar volume of any ideal gas at STP.
How many mL are in 1000 grams of water?
At 4 deg C and at a pressure of 760 mm of mercury, when water is at its highest density, 1000 grams of water will occupy 1000.028 mL. At all other temperatures (pressure = one atmosphere), it will occupy a greater volume. At 100 deg C it will occupy 1043 mL. However, most people will say 1000 grams of water equals 1000 mL.
What is the volume of 84.6 grams of helium at stp?
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
what volume in milliliters will 0.00922 g of H2 gas occupy at STP?
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
How many moles of of hydrogen gas occupy 112L at stp?
Ideal gas equation. PV = nRT ===============
How many grams of carbon dioxide will occupy a volume 500.0 ml at STP?
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. To convert 500.0 ml to liters, you divide by 1000 (since 1 liter = 1000 ml). Then, use the ideal gas law equation (PV = nRT) to find the number of moles of carbon dioxide, and finally convert moles to grams using the molar mass of CO2.
How many liters are in 3.50 grams of carbon monoxide at stp?
At STP (standard temperature and pressure), 1 mol of any gas occupies 22.4 liters. The molar mass of carbon monoxides is 28.01 g/mol. So, the number of moles in 3.50 grams of carbon monoxide can be calculated. Then, using the ideal gas law, you can determine that 3.50 grams of carbon monoxide at STP would be approximately 0.125 moles and would occupy around 2.8 liters (0.125 moles * 22.4 liters/mol).
What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
What volume does 0.685 moles of gas occupy at stp?
The volume is approx. 15,35 litres.
What volume (in liters) does 2.895 mole of oxygen occupy at STP?
The volume is 64,8 L.
What volume will 15 g of NH3 occupy at stp?
The volume of ammonia is 19,5 L.
One mole of N2 gas at STP will occupy what volume?
22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.
