At STP (Standard Temperature and Pressure: 0°C and 1 atm pressure), 1 mole of any gas occupies 22.4 L. Therefore, to find the number of moles of O gas in 10.0 L at STP, we divide 10.0 by 22.4 to get 0.4464 moles. The molar mass of oxygen (O₂) is 32 g/mol, so 0.4464 moles of O₂ gas would be 0.4464 moles * 32 g/mol ≈ 14.3 grams.
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
Ideal gas equation. PV = nRT ===============
This volume is 79,79 litres.
The volume is approx. 15,35 litres.
The volume is 64,8 L.
At STP (standard temperature and pressure), 32 grams of O2 would occupy the same volume as 22.4 liters, which is the molar volume of any ideal gas at STP.
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
Ideal gas equation. PV = nRT ===============
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. To convert 500.0 ml to liters, you divide by 1000 (since 1 liter = 1000 ml). Then, use the ideal gas law equation (PV = nRT) to find the number of moles of carbon dioxide, and finally convert moles to grams using the molar mass of CO2.
At STP (standard temperature and pressure), 1 mol of any gas occupies 22.4 liters. The molar mass of carbon monoxides is 28.01 g/mol. So, the number of moles in 3.50 grams of carbon monoxide can be calculated. Then, using the ideal gas law, you can determine that 3.50 grams of carbon monoxide at STP would be approximately 0.125 moles and would occupy around 2.8 liters (0.125 moles * 22.4 liters/mol).
This volume is 79,79 litres.
The volume is approx. 15,35 litres.
The volume is 64,8 L.
The volume of ammonia is 19,5 L.
22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.