0
How many grams of O are needed to produce 67.3 L of CO at standard conditions?
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?
16,45 g nitrogen are needed.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many grams of carbon dioxide are produced by the combustion of 224 liters of ethane gas CH in standard conditions?
88
What is neon's density in grams per centimeter cubed?
Neon has a density of 0.9002 grams per cubic centimeter at standard conditions (0 degrees Celsius and 1 atmosphere of pressure).
What volume of acetylene measured at standard conditions could be obtained from 10 grams of calcium carbide?
10 grams of calcium carbide can produce approximately 4.4 liters of acetylene gas at standard conditions (STP). This is calculated based on the stoichiometry of the reaction between calcium carbide and water to produce acetylene gas.
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?
16,45 g nitrogen are needed.
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
How many grams of mercury II oxide are needed to produce 1.56 L of oxygen gas according to the following reaction at 25C and 1 ATM?
You would need 5.7 grams of mercury II oxide to produce 1.56 L of oxygen gas according to the following reaction at those conditions.
How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many grams of potassium iodide will produce 750 grams of silver iodide when there is an excess of silver nitrate?
530,3 g potassium iodide are needed.
What is the volume occupied by 40 grams of argon gas Ar at standard conditions?
At standard conditions (0°C and 1 atm pressure), the molar volume of a gas is approximately 22.4 L/mol. Since the molar mass of argon (Ar) is 40 g/mol, 40 grams of argon gas would occupy approximately 22.4 liters at standard conditions.
How many grams of carbon dioxide are produced by the combustion of 224 liters of ethane gas CH in standard conditions?
88
How many grams of aluminum is required to produce 25.0 grams of aluminum sulfate?
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.
