a) ClF4- has a square planar geometry due to its five electron domains, with four bonding pairs and one lone pair. b) ClF4+ has a linear geometry with no lone pairs, resulting in a linear molecular shape. c) NO2- has a T-shaped geometry with three electron domains - one lone pair and two bonding pairs. d) BrF3 has a bent molecular geometry due to the presence of two lone pairs and two bonding pairs around the central atom. e) CO2 has a linear molecular geometry as it has two electron domains and no lone pairs around the central carbon atom.
OH alone would be linear shape AX1E3 bond angle 180o
.. _ .. N = N
Trigonal Pyramidal - 107.5 degrees It has 3 bonds and one lone pair. With all 4 elements (the 3 covalent bonds plus the lone pair) you would think it was Tetrahedral, with 109.5 degrees between them, but because the lone pair is there, it pushes the other bonding electrons closer together and thus you have a smaller angle of 107.5 degrees and the different shape.
1 Source: My online chemistry book.
The SF3+ molecule has a T-shaped molecular geometry, with three bonding pairs and two lone pairs around the sulfur atom.
a) ClF4- has a square planar geometry due to its five electron domains, with four bonding pairs and one lone pair. b) ClF4+ has a linear geometry with no lone pairs, resulting in a linear molecular shape. c) NO2- has a T-shaped geometry with three electron domains - one lone pair and two bonding pairs. d) BrF3 has a bent molecular geometry due to the presence of two lone pairs and two bonding pairs around the central atom. e) CO2 has a linear molecular geometry as it has two electron domains and no lone pairs around the central carbon atom.
In N2F2, each nitrogen atom forms a triple bond with the other nitrogen atom and a single bond with a fluorine atom. Therefore, there are 2 bond pairs and 1 lone pair on each nitrogen atom, making a total of 4 bond pairs and 2 lone pairs in N2F2.
EDTA has 6 lone pairs of electrons four from oxygen atoms and two from lone pairs on nitrogen. IN complex ions all boncds are dative covalent so both electrons come from the ligand ion this case edta. so the answer is 6 electron pairs (12 electrons) are added
The molecular shape for ( \text{PH}_4^+ ) (phosphonium ion) is tetrahedral. This is because phosphorus has four bonding pairs around it, which results in a geometry with bond angles of approximately 109.5 degrees.
There are infinitely many in each of the two curves/lines.
OH alone would be linear shape AX1E3 bond angle 180o
electron and an antineutrino through weak force interaction.
They are the coordinates of the infinitely many points on the line defined by the equation.
Group the numbers in pairs. You have ten pairs, each of which is equal to -1 and the ten are to be added together. Total = -10
.. _ .. N = N
2x plus 3y