.250 mole 7.02 ------ 28.09 = .250
To find the number of moles in 237 g of niobium, divide the given mass by the molar mass of niobium, which is approximately 92.91 g/mol. Number of moles = 237 g / 92.91 g/mol โ 2.55 moles.
11 g x 1 mol Si/28.0855 g Si= 0.39 mol Si 205g He x 1mol He/4.002602 g He=51.2 mol He
5 g of sulfur contain 0,94.10e23 atoms.
The number of atoms is 28,099.10e23.
The atomic mass of neptunium is approximately 237 grams per mole. Since 1 mole of any element contains Avogadro's number of atoms (approximately 6.022 x 10^23 atoms), one atom of neptunium would weigh approximately 237 grams divided by Avogadro's number, which is a very tiny fraction of a gram.
.250 mole 7.02 ------ 28.09 = .250
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
To find the number of moles in 237 g of niobium, divide the given mass by the molar mass of niobium, which is approximately 92.91 g/mol. Number of moles = 237 g / 92.91 g/mol โ 2.55 moles.
6,687.1023 chlorine atoms
The number of atoms of lead is 6,68.10e23.
1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.
11 g x 1 mol Si/28.0855 g Si= 0.39 mol Si 205g He x 1mol He/4.002602 g He=51.2 mol He
5 g of sulfur contain 0,94.10e23 atoms.
To find the number of moles in 245 g of silicon, divide the given mass by the molar mass of silicon. The molar mass of silicon is 28.09 g/mol. Therefore, 245 g รท 28.09 g/mol โ 8.71 moles of silicon.
The answer is 3.32*10^23 atoms
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.