To find the number of fluorine (F) atoms in 5.88 mg of ClF3, first calculate the molar mass of ClF3. ClF3 has a molar mass of 83.45 g/mol. Convert 5.88 mg to grams (0.00588 g) and then use the molar mass to find the number of moles of ClF3. Since there are 3 F atoms in each molecule of ClF3, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then by 3 to find the number of F atoms. In this case, there are approximately 4.24 x 10^20 F atoms in 5.88 mg of ClF3.
8,23.1023 atoms Mg is equivalent to 1,366 moles.
7,00 mg of allicin contain 0,519.10e20 sulfur atoms.
Magnesium nitrate (Mg(NO3)2) contains 1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms, totaling 9 atoms in a single molecule of Mg(NO3)2.
This is equivalent to 1,4 moles.
There are 9 atoms present in one molecule of Mg(NO3)2.
8,23.1023 atoms Mg is equivalent to 1,366 moles.
In 4 Mg(OH)2, there are 8 oxygen atoms, 4 magnesium atoms, and 8 hydrogen atoms, totaling to 20 atoms in total.
7,00 mg of allicin contain 0,519.10e20 sulfur atoms.
There are 9 atoms present in one molecule of Mg(NO3)2.
1 gram = 1000 mg
There are 12 atoms in one molecule of magnesium (Mg).
Magnesium nitrate (Mg(NO3)2) contains 1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms, totaling 9 atoms in a single molecule of Mg(NO3)2.
There are 5 atoms in Mg3P2, consisting of 3 magnesium (Mg) atoms and 2 phosphorus (P) atoms.
There are 14 atoms in Mg(C2H3O2)2. This includes one magnesium atom (Mg), four carbon atoms (C), six hydrogen atoms (H), and four oxygen atoms (O).
This is equivalent to 1,4 moles.
There are 9 atoms present in one molecule of Mg(NO3)2.
To convert atoms to moles, divide the number of atoms by Avogadro's number (6.022 x 10^23). In this case, 12.04 x 10^23 atoms / 6.022 x 10^23 atoms/mol = 2 moles of magnesium.