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5.88 mg ClF3 (1 gram/1000 mg)(1 mole ClF3/92.45 g)(3 mole F/1 mole ClF3)(6.022 X 10^23/1 mole F)
= 1.15 X 10^20 atoms of fluorine
Wiki User
∙ 12y ago
To find the number of fluorine (F) atoms in 5.88 mg of ClF3, first calculate the molar mass of ClF3. ClF3 has a molar mass of 83.45 g/mol. Convert 5.88 mg to grams (0.00588 g) and then use the molar mass to find the number of moles of ClF3. Since there are 3 F atoms in each molecule of ClF3, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then by 3 to find the number of F atoms. In this case, there are approximately 4.24 x 10^20 F atoms in 5.88 mg of ClF3.
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