To find the number of fluorine (F) atoms in 5.88 mg of ClF3, first calculate the molar mass of ClF3. ClF3 has a molar mass of 83.45 g/mol. Convert 5.88 mg to grams (0.00588 g) and then use the molar mass to find the number of moles of ClF3. Since there are 3 F atoms in each molecule of ClF3, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then by 3 to find the number of F atoms. In this case, there are approximately 4.24 x 10^20 F atoms in 5.88 mg of ClF3.
8,23.1023 atoms Mg is equivalent to 1,366 moles.
7,00 mg of allicin contain 0,519.10e20 sulfur atoms.
Magnesium nitrate (Mg(NO3)2) contains 1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms, totaling 9 atoms in a single molecule of Mg(NO3)2.
This is equivalent to 1,4 moles.
There are 9 atoms present in one molecule of Mg(NO3)2.
8,23.1023 atoms Mg is equivalent to 1,366 moles.
In 4 Mg(OH)2, there are 8 oxygen atoms, 4 magnesium atoms, and 8 hydrogen atoms, totaling to 20 atoms in total.
7,00 mg of allicin contain 0,519.10e20 sulfur atoms.
There are 9 atoms present in one molecule of Mg(NO3)2.
There are 12 atoms in one molecule of magnesium (Mg).
1 gram = 1000 mg
Magnesium nitrate (Mg(NO3)2) contains 1 magnesium atom, 2 nitrogen atoms, and 6 oxygen atoms, totaling 9 atoms in a single molecule of Mg(NO3)2.
There are 5 atoms in Mg3P2, consisting of 3 magnesium (Mg) atoms and 2 phosphorus (P) atoms.
There are 14 atoms in Mg(C2H3O2)2. This includes one magnesium atom (Mg), four carbon atoms (C), six hydrogen atoms (H), and four oxygen atoms (O).
There are 9 atoms present in one molecule of Mg(NO3)2.
This is equivalent to 1,4 moles.
To convert atoms to moles, divide the number of atoms by Avogadro's number (6.022 x 10^23). In this case, 12.04 x 10^23 atoms / 6.022 x 10^23 atoms/mol = 2 moles of magnesium.