The atomic number of hafnium is 72. So there is 72 protons.
To find the number of oxygen atoms in 3.33 grams of magnesium hydroxide, you first need to calculate the moles of magnesium hydroxide using its molar mass. Then, since the formula of magnesium hydroxide is Mg(OH)2, there are 2 oxygen atoms in each formula unit. Finally, multiply the number of moles by Avogadro's number to get the number of oxygen atoms.
Hafnium has 2 electrons in its first shell and 8 electrons in its second shell. Therefore, in the outer shell of hafnium, there are 2 + 8 = 10 valence electrons.
C + 2Cl2 ==> CCl4atoms of C needed = 2.00 mol Cl2 x 1 mole C/2 mole Cl2 x 6.02x10^23 atoms/mole = 6.02x10^23 atoms
The number of atoms is 45,166.10e23.
There are 0.1262 mol of H2SO4, which means there are 0.1262 mol * 2 = 0.2524 mol of hydrogen atoms (H) in total. Since each molecule of H2SO4 contains 2 hydrogen atoms, there are 0.2524 mol * 6.022 x 10^23 atoms/mol = approximately 1.52 x 10^23 hydrogen atoms in 0.1262 mol of H2SO4.
There are 3.12 x 10^23 chlorine atoms in 0.650 mol of Ca(ClO4)2. This is calculated by multiplying the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) and the number of chlorine atoms in one mole of Ca(ClO4)2 (2).
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
To determine the number of hydrogen atoms in 2 mol of C8H18, we first need to calculate the molar mass of C8H18. Carbon has a molar mass of approximately 12 g/mol, and hydrogen has a molar mass of approximately 1 g/mol. Therefore, the molar mass of C8H18 is (812) + (181) = 114 g/mol. Next, we use Avogadro's number (6.022 x 10^23) to calculate the number of molecules in 2 mol of C8H18, which is 2 mol * 6.022 x 10^23 molecules/mol. Since there are 18 hydrogen atoms in each molecule of C8H18, the total number of hydrogen atoms in 2 mol of C8H18 is 2 mol * 6.022 x 10^23 molecules/mol * 18 atoms/molecule = 2.17 x 10^25 hydrogen atoms.
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
To calculate the number of atoms in 64 grams of sulfur, you first need to determine the molar mass of sulfur (32 g/mol). Then, you divide the given mass by the molar mass to find the number of moles (64 g / 32 g/mol = 2 mol). Finally, you use Avogadro's number (6.022 x 10^23) to find the number of atoms in 2 moles of sulfur, which would be 2 mol x 6.022 x 10^23 atoms/mol.
One molecule of sulfuric acid, H2SO4, contains 7 atoms (2 hydrogen, 1 sulfur, and 4 oxygen). Therefore, in 1.5 mol of sulfuric acid, there would be 1.5 x 6.022 x 10^23 atoms, which is approximately 9.033 x 10^23 atoms.
There are 2 atoms of chlorine and 1 atom of barium in each molecule of barium chloride (BaCl2). Therefore, in 0.550 mol of BaCl2, there are 0.550 mol x (1 Ba + 2 Cl) = 0.550 x 3 = 1.65 mol total atoms.
There are 9.72 mol of oxygen atoms in 2.15 mol of N2O. This is because each molecule of N2O contains 2 oxygen atoms. So, you can calculate the number of oxygen atoms by multiplying the number of moles of N2O by 2.
To find the number of atoms in 1.25x10^4 mol of mercury, you need to use Avogadro's number, which is 6.022x10^23 atoms/mol. Multiply the number of moles by Avogadro's number: 1.25x10^4 mol * 6.022x10^23 atoms/mol = 7.5275x10^27 atoms in 1.25x10^4 mol of mercury.
The atomic number of hafnium is 72. So there is 72 protons.
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms