55.8 grams
There are 2 moles of atoms in 12.0 grams of helium. Helium has a molar mass of 4 g/mol and each mole contains 6.02 x 10^23 atoms. Calculating the number of moles: 12 g / 4 g/mol = 3 moles. And then, 3 moles * 6.02 x 10^23 atoms/mol = 1.81 x 10^24 atoms.
One atom of mercury (Hg) contains roughly 6.022 x 10^23 atoms, which is known as Avogadro's number. Thus, there is one mole of mercury atoms in one atom of Hg.
There are approximately 6.022 x 10^22 atoms in one mole of any element. The molar mass of mercury is about 200.59 g/mol. First, determine the mass of 9.1 cubic centimeters of mercury using its density. Then, convert this mass to moles and finally to atoms by using Avogadro's number.
No, Hg is the chemical symbol for mercury, which is a metallic element. Mercury exists as individual atoms, not molecules.
There are 1.92 x 10^23 atoms in 0.3173 mol of Hg. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of Hg.
The molar mass of mercury (Hg) is 200.59 g/mol. In 200.6g, there would be 1 mole of Hg, which is equal to 6.022 x 10^23 atoms. In 400.1g, there would be 2 moles of Hg, which is equal to 1.2044 x 10^24 atoms.
To find the number of atoms in 1.25x10^4 mol of mercury, you need to use Avogadro's number, which is 6.022x10^23 atoms/mol. Multiply the number of moles by Avogadro's number: 1.25x10^4 mol * 6.022x10^23 atoms/mol = 7.5275x10^27 atoms in 1.25x10^4 mol of mercury.
There are 5 atoms in Hg2Cl2: 2 mercury atoms (Hg) and 3 chlorine atoms (Cl).
55.8 grams
The balanced chemical equation for the reaction is Hg + S -> HgS. The molar mass of Hg is 200.59 g/mol and HgS is 232.66 g/mol. To form 1 mol of HgS, 1 mol of S is required. Calculate the amount of S needed using the given mass of Hg.
The molecular weight of mercury (Hg) is approximately 200.59 g/mol.
There are 2 moles of atoms in 12.0 grams of helium. Helium has a molar mass of 4 g/mol and each mole contains 6.02 x 10^23 atoms. Calculating the number of moles: 12 g / 4 g/mol = 3 moles. And then, 3 moles * 6.02 x 10^23 atoms/mol = 1.81 x 10^24 atoms.
To calculate the grams of mercuric chloride needed, we must first find the molar mass of HgCl2 (molar mass = 200.59 g/mol). Then, calculate the moles of mercury in 5.11g (moles = 5.11g / molar mass of Hg = 0.032 mol). Since the ratio of HgCl2:Hg is 3:1 in the balanced equation, you would need 0.032 mol of HgCl2 (0.032 mol Hg x 1 mol HgCl2 / 1 mol Hg = 0.032 mol HgCl2) which is equal to 6.42g of HgCl2 (0.032 mol HgCl2 x molar mass of HgCl2 = 6.42g).
The molar mass of Hg is 200.59 g/mol and of O is 16.00 g/mol. HgO consists of 1 Hg and 1 O atom, so the molar mass of HgO is 200.59 + 16.00 = 216.59 g/mol. To find the mass of mercury produced, we calculate the molar mass ratio of Hg to HgO: (200.59 g/mol Hg) / (216.59 g/mol HgO) = 0.926. When 16 grams of HgO are heated, the mass of mercury produced would be 16 g * 0.926 ≈ 14.82 grams.
There are five atoms in Hg2SCl2: 2 atoms of mercury (Hg), 1 atom of sulfur (S), and 2 atoms of chlorine (Cl).
0.0113 mol oxygen