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How many k ions ain 6.76 mol of K3PO4?
MW =3*39+1*31+4*16 = 212 in K3Po43 mol K+ ions produce. 1 mol weigh = 212 contain 3x6.023x10^23 K+ ions 6.76g contain = 6.76 x 3 moles K+ x 6.023x10^23 / 212 g/mol = 5.76x10^22
How many potassium atoms are in 0.0384 mole K?
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
How many moles of KBr will be produced from 14.17 moles of BaBr2?
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
What is the molecular mass for the chemical K2O?
The molar mass of K2O is calculated as follows: (2 atoms of K x atomic mass of K) + (1 atom of O x atomic mass of O) = (2 x 39.10 g/mol) + (1 x 16.00 g/mol) = 94.20 g/mol.
What is the chemical formula of KCIO4?
in 1 mol (6.023x10^23) of the substance there would be: 6.023x10^23 atoms of K (potassium) 6.023x10^23 atoms of C (Carbon) 6.023x10^23 atoms of I (Iodine) and 2.408x10^24 atoms of O (Oxygen)
How many atoms of K in 2.77g of KCl?
To find the number of K atoms in KCl, we first calculate the molar mass of KCl: 39.10 (K) + 35.45 (Cl) = 74.55 g/mol. Next, we determine the number of moles of KCl in 2.77g: 2.77g / 74.55 g/mol = 0.0371 mol. Since there is 1 K atom in 1 KCl molecule, the number of K atoms in 2.77g of KCl is the same as the number of moles of KCl, which is 0.0371 mol.
How many atoms are in 0.0671 mol K?
There are 4.05 x 10^22 atoms in 0.0671 mol of potassium (K). This is calculated by multiplying the Avogadro's number (6.022 x 10^23) by the number of moles.
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
How do you find the mass of a sample of 1.72 x 1023 atoms of potassium?
To find the mass of the sample, you would first determine the molar mass of potassium (approximately 39.1 g/mol). Then, you would multiply the number of atoms by the molar mass to find the total mass. In this case, you would calculate (1.72 x 10^23 atoms) x (39.1 g/mol) = mass of the sample.
Calculate the number of atoms in 0.551 g of potassium K?
To calculate the number of atoms in 0.551 g of potassium (K), you first need to convert the mass to moles using the molar mass of potassium (39.10 g/mol). Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, 0.551 g of potassium would contain approximately 7.1 x 10^22 atoms.
How many atoms are there in 1.25 mol of silver?
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms
How many grams in 1.90 moles of K?
To convert from moles to grams, we need to use the molar mass of the element. The molar mass of potassium (K) is approximately 39.10 g/mol. So, for 1.90 moles of K, the mass would be 1.90 moles * 39.10 g/mol = 74.29 grams.
How many k ions ain 6.76 mol of K3PO4?
MW =3*39+1*31+4*16 = 212 in K3Po43 mol K+ ions produce. 1 mol weigh = 212 contain 3x6.023x10^23 K+ ions 6.76g contain = 6.76 x 3 moles K+ x 6.023x10^23 / 212 g/mol = 5.76x10^22
What is the average velocity of atoms in 2.00 mol of neon at 308 K?
The root mean square velocity of atoms in a gas can be calculated using the formula: vrms = sqrt((3kT)/m), where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the gas. For neon with a molar mass of 20.18 g/mol, the vrms at 308 K would be approximately 516 m/s.
What is the value for G at 100 K if H 27 kJ mol and S 0.09 kJ molK?
G=18 kJ/mol
What is the value for G at 300 K if H 27 kJmol and S 0.09 kJmolK?
G = 0 kJ/mol
How many potassium atoms are in 0.0384 mole K?
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
