0.0602 mole K x 6.02x10^23 atoms/mole = 3.62x10^22 atoms
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∙ 7y agoMW =3*39+1*31+4*16 = 212 in K3Po43 mol K+ ions produce. 1 mol weigh = 212 contain 3x6.023x10^23 K+ ions 6.76g contain = 6.76 x 3 moles K+ x 6.023x10^23 / 212 g/mol = 5.76x10^22
The molar mass of K2O is calculated as follows: (2 atoms of K x atomic mass of K) + (1 atom of O x atomic mass of O) = (2 x 39.10 g/mol) + (1 x 16.00 g/mol) = 94.20 g/mol.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
in 1 mol (6.023x10^23) of the substance there would be: 6.023x10^23 atoms of K (potassium) 6.023x10^23 atoms of C (Carbon) 6.023x10^23 atoms of I (Iodine) and 2.408x10^24 atoms of O (Oxygen)
To find the number of K atoms in KCl, we first calculate the molar mass of KCl: 39.10 (K) + 35.45 (Cl) = 74.55 g/mol. Next, we determine the number of moles of KCl in 2.77g: 2.77g / 74.55 g/mol = 0.0371 mol. Since there is 1 K atom in 1 KCl molecule, the number of K atoms in 2.77g of KCl is the same as the number of moles of KCl, which is 0.0371 mol.
There are 4.05 x 10^22 atoms in 0.0671 mol of potassium (K). This is calculated by multiplying the Avogadro's number (6.022 x 10^23) by the number of moles.
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
To find the number of moles, you first need to calculate the molar mass of potassium (39.10 g/mol). Then, divide the given mass (449g) by the molar mass to get the number of moles. In this case, 449g of potassium would contain approximately 11.5 moles.
To calculate the number of atoms in 0.551 g of potassium (K), you first need to convert the mass to moles using the molar mass of potassium (39.10 g/mol). Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, 0.551 g of potassium would contain approximately 7.1 x 10^22 atoms.
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms
To convert from moles to grams, we need to use the molar mass of the element. The molar mass of potassium (K) is approximately 39.10 g/mol. So, for 1.90 moles of K, the mass would be 1.90 moles * 39.10 g/mol = 74.29 grams.
MW =3*39+1*31+4*16 = 212 in K3Po43 mol K+ ions produce. 1 mol weigh = 212 contain 3x6.023x10^23 K+ ions 6.76g contain = 6.76 x 3 moles K+ x 6.023x10^23 / 212 g/mol = 5.76x10^22
The root mean square velocity of atoms in a gas can be calculated using the formula: vrms = sqrt((3kT)/m), where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the gas. For neon with a molar mass of 20.18 g/mol, the vrms at 308 K would be approximately 516 m/s.
G=18 kJ/mol
G = 0 kJ/mol
The molar mass of K2O is calculated as follows: (2 atoms of K x atomic mass of K) + (1 atom of O x atomic mass of O) = (2 x 39.10 g/mol) + (1 x 16.00 g/mol) = 94.20 g/mol.