To calculate the number of hydrogen atoms in 167 grams of propane (C3H8), first calculate the molar mass of propane (3 carbon atoms x 12.01 g/mol + 8 hydrogen atoms x 1.008 g/mol) = 44.1 g/mol. Next, use the formula: number of moles = mass / molar mass (167 g / 44.1 g/mol ≈ 3.79 mol). Since there are 8 hydrogen atoms per molecule of propane, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the total number of hydrogen atoms. The result is approximately 2.28 x 10^24 hydrogen atoms.
45,0 grams of hydrogen gas have 135,5.10e23 atoms.
To calculate the number of atoms in 3.4 grams of hydrogen peroxide, you first convert the grams to moles using the molar mass of hydrogen peroxide. Then, you use Avogadro's number to convert moles to atoms. There are approximately 6.022 x 10^23 atoms in 1 mole of a substance.
3.05 x 1025
It is the sum of the atomic weights of atoms contained in the molecule, expressed in grams.
6.6x1022 per gram of water
45,0 grams of hydrogen gas have 135,5.10e23 atoms.
To calculate the number of atoms in 3.4 grams of hydrogen peroxide, you first convert the grams to moles using the molar mass of hydrogen peroxide. Then, you use Avogadro's number to convert moles to atoms. There are approximately 6.022 x 10^23 atoms in 1 mole of a substance.
1,25 grams of CH4 contain 0,156696.10e23 atoms.
3.05 x 1025
Approx 6.01*10^23 atoms.
Approx 1.5*10^23 atoms.
hydrogen is H2, with a molecuar weight of 2.016. In 1.008 grams of H2 there are 3.011 X 10 raised to power 23 (approx) 2.011 X 1023 molecules or 6.022 X 1023 atoms. Ovviously you can go straight to the answer as the weight is the atomic mass in grams.
To find the number of hydrogen atoms in 5.839 grams of C8H8, first calculate the molar mass of C8H8, which is 104 g/mol. Next, find the number of moles of C8H8 in 5.839 grams using the molar mass. Since there are 8 hydrogen atoms per molecule of C8H8, multiply the number of moles by 8 to get the number of hydrogen atoms.
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
How_many_hydrogen_atoms_are_in_5.839_grams_of_c8h8Same question answered.
To determine how many hydrogen atoms are in 301 grams of H2O, we need to consider the molar mass of water (H2O). The molar mass of water is approximately 18 grams/mole. Since the molecular formula of water is H2O, it contains 2 hydrogen atoms. Using this information, we can calculate the number of moles in 301 grams of water and then determine the number of hydrogen atoms present.
It is the sum of the atomic weights of atoms contained in the molecule, expressed in grams.