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To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
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How would you prepare a 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water?
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
How much gm of disodium edta require to prepare 0.05 m disodium edta solution?
To prepare a 0.05 M disodium EDTA solution, you would need to dissolve 3.72 grams of disodium EDTA dihydrate (Na2C10H14N2Na2·2H2O) in enough water to make 1 liter of solution.
How would one prepare 10 ml of a 25 M HCI solution if 1 M HCI was available?
To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.
How do you prepare 10 mm solution with 4 m stock solution?
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
How you prepare 3 M KCl solution?
Weigh 22.35 grams of KCl and Dissolve in 100 mL of Distilled Water
How do you prepare 10 mm solution with 4 m stock solution?
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
What volume of a 2.5 M stock solution of acetic acid (HCHÀO) is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
To prepare a 0.50 M acetic acid solution, you would need to dilute the 2.5 M stock solution. By using the formula M1V1 = M2V2, you can calculate the volume of the stock solution needed as: (0.5 M)(100.0 mL) = (2.5 M)(V2), where V2 is the volume of the stock solution needed. So, V2 = (0.5 M x 100.0 mL) / 2.5 M = 20.0 mL. Therefore, you would need 20.0 mL of the 2.5 M stock solution to prepare the desired 100.0 mL of 0.50 M acetic acid solution.
Preparation of 0 38 M sodium acetate solution?
To prepare a 0.38 M sodium acetate solution, you would need to dissolve the appropriate amount of sodium acetate trihydrate (CH₃COONa·3H₂O) in water. For example, to make 100 mL of a 0.38 M solution, you would dissolve 2.96 grams of sodium acetate trihydrate in sufficient water to make 100 mL. Ensure complete dissolution before use.
What is the molality of a solution of chlorine and water is 0.0362 m how much chlorine in grams was used to prepare this solution?
To find the amount of chlorine used, we need to know the molar mass of chlorine. We can use the molality to calculate the moles of chlorine in the solution. Finally, we can convert moles to grams using the molar mass of chlorine to find the grams of chlorine used.
How many milliliters of 6.0 M NaOH must be used to prepare 1.0 liter of 0.10 M solution?
To prepare a 0.10 M NaOH solution, you need to dilute the 6.0 M solution. You can use the formula: M1V1 = M2V2 where M1 = 6.0 M, V1 is the volume of 6.0 M NaOH needed, M2 = 0.10 M, and V2 = 1000 mL (1.0 L). By substituting the values into the formula, you can calculate the volume of the 6.0 M NaOH needed to prepare the 0.10 M solution.
How would you prepare a 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water?
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
How much of a 0.250 M sucrose solution must be used to prepare 400.0 mL of a 0.0310 M solution?
You would need to use 17.5 mL of the 0.250 M sucrose solution to prepare 400.0 mL of a 0.0310 M solution. This can be calculated using the formula: C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration, and V2 is the final volume.
What volume of 2.5 m stock solution of acetic acid hc2h3o2 is required to prepare 100 mll of a .50 m acetic acid solution?
To prepare a 0.5 M acetic acid solution using a 2.5 M stock solution, you will need to dilute it. The formula for dilution is C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. Plugging in the values, you will need 20 ml of the 2.5 M stock solution to make 100 ml of a 0.5 M acetic acid solution.
How do you prepare 1 L of 15 M sodium hydroxide solution by diluting the stock solution of 6 M sodium hydroxide?
To prepare 1 L of 15 M NaOH solution, you need to dilute the 6 M stock solution. You would need to take 500 mL of the 6 M NaOH stock solution and add water to bring the total volume up to 1 L. This will give you a final concentration of 15 M.
What volume of a 1.50 M HCl solution should you use to prepare 2.00 L of a 0.100 M HCl solution?
To prepare a 0.100 M HCl solution from a 1.50 M HCl solution, you need to use the dilution formula, which is M1V1 = M2V2. You would need to use (V_1 = \frac{M_2V_2}{M_1}) to calculate the volume needed. Plugging in the values, you would need to use ( V_1 = \frac{0.100 M \times 2.00 L}{1.50 M} = 0.133 L or 133 mL) of the 1.50 M HCl solution.
How much gm of disodium edta require to prepare 0.05 m disodium edta solution?
To prepare a 0.05 M disodium EDTA solution, you would need to dissolve 3.72 grams of disodium EDTA dihydrate (Na2C10H14N2Na2·2H2O) in enough water to make 1 liter of solution.
How many Ml of 14.5 M NH3 are needed to prepare 2.00 L of a 1.00 M solution?
To prepare a 1.00 M solution from a 14.5 M NH3 solution, you'll need to dilute it. By using the formula: M1V1 = M2V2, you can calculate the volume of 14.5 M NH3 needed. Plugging in the values, you get 138 mL of 14.5 M NH3 needed.
