You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
To prepare a 0.05 M disodium EDTA solution, you would need to dissolve 3.72 grams of disodium EDTA dihydrate (Na2C10H14N2Na2·2H2O) in enough water to make 1 liter of solution.
To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
Weigh 22.35 grams of KCl and Dissolve in 100 mL of Distilled Water
To prepare a 0.50 M acetic acid solution, you would need to dilute the 2.5 M stock solution. By using the formula M1V1 = M2V2, you can calculate the volume of the stock solution needed as: (0.5 M)(100.0 mL) = (2.5 M)(V2), where V2 is the volume of the stock solution needed. So, V2 = (0.5 M x 100.0 mL) / 2.5 M = 20.0 mL. Therefore, you would need 20.0 mL of the 2.5 M stock solution to prepare the desired 100.0 mL of 0.50 M acetic acid solution.
To prepare a 0.10 M NaOH solution, you need to dilute the 6.0 M solution. You can use the formula: M1V1 = M2V2 where M1 = 6.0 M, V1 is the volume of 6.0 M NaOH needed, M2 = 0.10 M, and V2 = 1000 mL (1.0 L). By substituting the values into the formula, you can calculate the volume of the 6.0 M NaOH needed to prepare the 0.10 M solution.
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
You would need to use 17.5 mL of the 0.250 M sucrose solution to prepare 400.0 mL of a 0.0310 M solution. This can be calculated using the formula: C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration, and V2 is the final volume.
To prepare a 0.5 M acetic acid solution using a 2.5 M stock solution, you will need to dilute it. The formula for dilution is C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. Plugging in the values, you will need 20 ml of the 2.5 M stock solution to make 100 ml of a 0.5 M acetic acid solution.
To prepare 1 L of 15 M NaOH solution, you need to dilute the 6 M stock solution. You would need to take 500 mL of the 6 M NaOH stock solution and add water to bring the total volume up to 1 L. This will give you a final concentration of 15 M.
To prepare a 0.100 M HCl solution from a 1.50 M HCl solution, you need to use the dilution formula, which is M1V1 = M2V2. You would need to use (V_1 = \frac{M_2V_2}{M_1}) to calculate the volume needed. Plugging in the values, you would need to use ( V_1 = \frac{0.100 M \times 2.00 L}{1.50 M} = 0.133 L or 133 mL) of the 1.50 M HCl solution.
To prepare a 0.05 M disodium EDTA solution, you would need to dissolve 3.72 grams of disodium EDTA dihydrate (Na2C10H14N2Na2·2H2O) in enough water to make 1 liter of solution.
To prepare a 1.00 M solution from a 14.5 M NH3 solution, you'll need to dilute it. By using the formula: M1V1 = M2V2, you can calculate the volume of 14.5 M NH3 needed. Plugging in the values, you get 138 mL of 14.5 M NH3 needed.
To prepare a 1 M solution from a 6 M solution, you can dilute the 6 M solution by adding 5 parts of solvent to 1 part of the 6 M solution. For example, to make 1 L of 1 M solution from 6 M stock, you would mix 166.7 mL of the 6 M solution with 833.3 mL of solvent (usually water).
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To prepare a 1.00 M solution, you would need to dilute the 12.0 M solution. Using the formula CsVs = CdVd where Cs is the initial concentration, Vs is the initial volume, Cd is the desired concentration, and Vd is the desired volume, you can calculate the volume needed: (12.0 M)(V1) = (1.00 M)(75.0 ml). Solving for V1, you get V1 = 6.25 ml. So, 6.25 ml of the 12.0 M solution would be needed to prepare a 1.00 M solution.