To prepare a 1% salicylic acid ointment that is 15 g in size, you would need 0.15 g of salicylic acid. This is calculated by multiplying 15 g by 0.01 (1%). Therefore, 0.15 g of salicylic acid would be required for the preparation.
Preparation of standards Prepare a stock uric acid solution of 100 mg/L. Dilute it to give working concentrations of 10, 20, 30, 40, 50 and 60 mg/L. Procedure:1 Prepare a 100 mg/L stock solution of uric acid Weigh out 100 mg uric acid, transfer it to a 1 L volumetric flash, add about 900 ml distilled water, and then add about 100 µl of 0.6 N NaOH to help dissolve the uric acid. Make up to the volume with water when uric acid is fully dissolved.2 Dilute the stock solution to give working concentrations of 10, 20, 30, 40, 50, 60 mg/L. To prepare 50 ml of the working standards 5, 10, 20, 30, 40, 50 mg/L respectively, weigh 10, 15, 20, 25, 30 g of stock solution into 50 ml volumetric flasks and make up to volume with distilled water.
To prepare a 0.1 N solution of perchloric acid, you would need to dissolve 3.65 grams of perchloric acid (HClO4) in 1 liter of water. This solution would then have a normality of 0.1 N, meaning it contains 0.1 mole of perchloric acid per liter of solution.
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
To prepare a 1M solution of NaCl, dissolve 58.44 grams of NaCl in water and dilute to 1 liter with water. This will give you a solution where the concentration of NaCl is 1 mole per liter.
To prepare a 2 molar salicylic acid solution, you would need to dissolve 17.5 grams of salicylic acid in enough water to make 1 liter of solution. First, measure out the salicylic acid using a balance, then add it to a beaker or flask with some water and stir until dissolved. Finally, add more water to bring the volume up to 1 liter, and mix well to ensure uniform concentration.
To prepare a 1% salicylic acid ointment that is 15 g in size, you would need 0.15 g of salicylic acid. This is calculated by multiplying 15 g by 0.01 (1%). Therefore, 0.15 g of salicylic acid would be required for the preparation.
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
To prepare 0.1 N oxalic acid solution, you would need to dissolve 0.634 g of oxalic acid dihydrate (H2C2O4·2H2O) in distilled water and make up the solution to a final volume of 1 liter. This will give you a 0.1 N (normality) solution of oxalic acid.
The theoretical yield of acetylsalicylic acid can be calculated based on the stoichiometry of the reaction between salicylic acid and acetic anhydride. For every 1 mole of salicylic acid reacted, 1 mole of acetylsalicylic acid is formed. Given the molecular weights of salicylic acid and acetylsalicylic acid, the expected yield can be calculated using the formula: expected yield (g) = (actual mass of salicylic acid / molecular weight of salicylic acid) x (molecular weight of acetylsalicylic acid).
To prepare a saturated solution of oxalic acid, dissolve 1 gram of oxalic acid in 7 grams of water at a given temperature until no more oxalic acid can dissolve. This will result in a saturated solution where the maximum amount of oxalic acid has dissolved in the water at that temperature.
Since salicylic acid is being reacted with excess acetic anhydride, salicylic acid is the limiting reactant of the reaction. The balanced equation of the reaction of salicylic acid and acetic anhydride indicates that their is a 1:1:1:1 ratio between every reactant and product. Based on this, it can be concluded that the moles of salicylic acid, if reacted entirely, will yield an equivalent amount of moles of aspirin. To find the theoretical yield, you must know the molecular weight of aspirin and salicylic acid. First, the amount of moles of salicylic acid must be calculated by dividing the gram amount of salicylic acid, which is 85 grams, and dividing it by its molecular weight, which is 138.12 grams per mole.85.0/138.12= 0.615 moles of salicylic acidThis is the mole amount of salicylic acid as well as the theoretical mole amount of aspirin. To convert the mole amount of aspirin into grams, this figure be multiplied by the molecular weight of aspirin, which is 180.15980.615 x 180.1598 = 111 grams of aspirin (when rounded to 3 significant figures)
To prepare a 1% nitric acid solution, you would mix 1 part of concentrated nitric acid with 99 parts of water (1:99 dilution). Always add acid to water slowly to avoid splashing. Use appropriate personal protective equipment when handling nitric acid due to its corrosive nature.
To prepare a 10M solution of acetic acid, dissolve 60.05g of glacial acetic acid (CH3COOH) in enough water to make a final volume of 1 liter. The molar mass of acetic acid is 60.05 g/mol. Make sure to wear appropriate safety gear, as acetic acid is corrosive.
Salicylic acid is a benzene ring with two neighboring functional groups. One is a carboxylic acid (COOH) the other is a hydroxl (OH) When Bicarbonate(HCO3) is added to water with salicylic acid, the -HCO3 pulls the proton off of the hydroxyl making it a salicylate ion. Salicylate ion has a greater solubility than salicylic acid. I think. That's what 1 semester of Ochem will do for you.
Use a 1-2% Salicylic acid lotion or gel on the affected area daily. Salicylic acid dissolves the sebum in the pore that causes the blackheads.