Because you asked how to make a 9 g/L solution of NaCl rather than a 9.0 g/L, or a 9.00 g/L solution, to make a 9 g/L solution of NaCl you first weigh out 9 g of dry NaCl. The weight, actually mass, of the NaCl needs to be 9 g plus or minus 1 g. Next, add the 9 g of NaCl to less than one liter of water, perhaps 25 or 50 mL less. Stir or shake the flask very well for several minutes after all of the NaCl has dissolved, then bring the total volume up to nearly 1 L. Stir or shake the flask very well again, then add water if necessary to ensure that the total volume is one liter.
To calculate the mass of NaCl needed for a 3.00M solution in 1.00 liter: Calculate the molar mass of NaCl (58.44 g/mol). Use the formula Molarity (M) = moles of solute/liters of solution. Convert molarity to moles (3.00 mol/L x 1.00 L = 3.00 mol). Convert moles to grams (3.00 mol x 58.44 g/mol = 175.32 grams). You would need 175.32 grams of NaCl to make 1.00 liter of a 3.00M NaCl solution.
To make a two mole salt solution in two liters of water, you'll need 4 moles of salt (2 moles/L * 2 L = 4 moles). The molar mass of salt (NaCl) is approximately 58.44 g/mol, so 4 moles would be 233.76 grams (4 moles * 58.44 g/mol = 233.76 g).
Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)
26.8125 g
To prepare a 100 mM NaCl solution, you would need to dissolve 5.84 grams of NaCl in water to make a final volume of 1 liter. This calculation is based on the molar mass of NaCl (58.44 g/mol) and the definition of molarity (Molarity = moles of solute / volume of solution in liters).
The molar mass of NaCl is 58.44 g/mol. To find the moles of solute, divide the mass by the molar mass: 526 g / 58.44 g/mol = 9.0 mol. To make a 3.0 M solution, divide the moles by the concentration: 9.0 mol / 3.0 mol/L = 3.0 L. Therefore, the volume of the solution is 3.0 liters.
To find the molarity of the solution, first calculate the number of moles of sodium sulfate by dividing the mass (15.5g) by the molar mass of sodium sulfate (142.04 g/mol). Next, convert the volume of the solution to liters (35 ml = 0.035 L). Finally, divide the number of moles by the volume in liters to get the molarity of sodium sulfate in the solution.
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
To prepare a 6M NaCl solution, you would need to dissolve 58.44 grams of NaCl in water to make a 1 liter solution. To prepare a different volume, you would adjust the amount of NaCl accordingly using the molarity equation: Molarity = moles of solute / volume of solution in liters.
You would need to dissolve 14.62 grams of NaCl in water to make a 0.5M NaCl solution with a final volume of 500 ml. This calculation is based on the formula: moles = Molarity x Volume (in liters), and then converting moles to grams using the molecular weight of NaCl.
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.
You need 841,536 g NaCl.
0.5 M means 0.5 moles per liter. so it depends on how many liters of solution that you need.Suppose you want to make 1 liter of solution, then you need 0.5 moles of NaClFrom the webelements.com Periodic Table:Atomic mass of Sodium (Na) = 22.990 & Atomic Mass of Chlorine (Cl) = 35.453So 1 mole of NaCl = (22.990 + 35.453) grams = 58.443 gramsBased on the 1 liter, we want to add 0.5 moles: (58.443 grams/mole)*(0.5 mole) = 29.2215 g (to make 1 liter of 0.5 M solution)
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
To calculate the mass of NaCl needed for a 3.00M solution in 1.00 liter: Calculate the molar mass of NaCl (58.44 g/mol). Use the formula Molarity (M) = moles of solute/liters of solution. Convert molarity to moles (3.00 mol/L x 1.00 L = 3.00 mol). Convert moles to grams (3.00 mol x 58.44 g/mol = 175.32 grams). You would need 175.32 grams of NaCl to make 1.00 liter of a 3.00M NaCl solution.
To make a two mole salt solution in two liters of water, you'll need 4 moles of salt (2 moles/L * 2 L = 4 moles). The molar mass of salt (NaCl) is approximately 58.44 g/mol, so 4 moles would be 233.76 grams (4 moles * 58.44 g/mol = 233.76 g).