Balance the oxidation states on the atoms in the molecule.
An oxide always contains oxygen in -2 oxidation state , in ionic compounds this is O2-.
As the chromium is Cr(IV) in +4 oxidation state, ( shown as an ion Cr4+ ) you can balance the states or charges which ever way to get
CrO2 (which you can write as Cr4+ (O2-)2 )
Chromite is an iron chromium oxide: FeCr 2 O 4
From the formula, you have 2 atoms of Magnesium combine with one oxygen molecule to form 2 molecules of magnesium oxide. So when 4 magnesium atoms combine with two molecules of oxygen you get 4 magnesium oxide molecules. So from 4 moles of magnesium you get 4 moles of Magnesium oxide.
The chemical formula of this is MnO2.It is brown in colour. The oxidation number of Mn is 4 in this compound.
If the balanced chemical equation for the reaction is given, we can determine the stoichiometry of the reaction. For the formation of magnesium oxide (MgO) from magnesium (Mg) and oxygen (O2), the balanced equation is: [2Mg + O2 \rightarrow 2MgO]. This means that 2 moles of Mg form 2 moles of MgO. Therefore, with 4 moles of Mg, 4 moles of MgO would be formed in this reaction.
That's old-fashioned nomenclature, but that's okay - the "-ic" suffix means you're dealing with tin with a higher number of valence electrons, in this case, 4. So with tin as +4 and oxygen, as always, as -2, you're going to get a formula of SnO2. Tin with a charge of +2 is the other possible valence option, and that's called "stannous oxide" with the "-ous" suffix, and a formula of SnO. The better way to express stannic oxide is simply to say tin(IV) oxide, and stannous oxide as tin(II) oxide.
The correct formula for nitrogen 4 oxide is N2O4.
Lead(IV) oxide would have the formula PbO2
Chromium has four oxidation states: 2, 3, 4, and 6.Iodine has one, and it's -1.There will be a iodide for each oxidation state of chromium.CrI2 Chromium (II) iodideCrI3 Chromium (III) iodideCrI4 Chromium (IV) iodideCrI6 Chromium (VI) iodide
TiO
In acidic conditions, chromium(III) oxide undergoes disproportionation, forming chromium(II) ions and chromium(VI) ions. The overall reaction is: 2Cr2O3 + 4H+ -> 2Cr3+ + Cr2O7^2- + 2H2O
The chemical formula for the compound formed between chromium III and borate is Cr(B(OH)4)3.
(Pb2)O
Cr(SCN)3 is the chemical formula for the Chromium (III) Thiocyanate. This is because Chromium (III) has a charge of +3 while Thiocyanate has a charge of -1. To balance the charges, we switch the 2 charges. So we have 1 ion of chromium (III) with 3 ions of thiocyanate.
Chromite is an iron chromium oxide: FeCr 2 O 4
The ionic formula for lead (IV) oxide is PbO2. In this compound, lead is in the +4 oxidation state and oxygen is in the -2 oxidation state.
The chemical formula for stannic oxide is SnO2, where Sn represents the element tin and O represents oxygen. Stannic oxide is a compound where tin is in the +4 oxidation state.
It is SnO2Why? Because:Tin has a charge of 4 and Oxygen has a charge of 2. Their charges are switched to make a compound; therefore, the chemical formula would be written as Sn2O4. Then, you have to simplify that so it would be written as SnO2.