A guy wire anchor is used to secure the guy wire to the ground or structure. It helps provide stability and support to the structure, particularly in situations where the structure needs to withstand tension or lateral forces.
The guy wire forms a right triangle with the pole and the ground. Using the Pythagorean theorem (a^2 + b^2 = c^2), we can calculate the length of the guy wire. In this case, a = 10 ft, b = 15 ft, so the length of the guy wire (c) is √(10^2 + 15^2) = √(100 + 225) = √325 ≈ 18.03 ft.
The guy wire, pole, and ground form a right triangle. Using the Pythagorean theorem (a^2 + b^2 = c^2), where a = 4m and b = 6m, we can solve for the length of the guy wire (c). Thus, c = √(4^2 + 6^2) = √(16 + 36) = √52 meters, or approximately 7.2 meters long.
I'm unable to draw diagrams. However, you can visualize the scenario with the tower standing vertically. One side of the triangle represents the tower (115m) and the other side the anchor point on the ground (24m). The guy wire forms the hypotenuse of the right triangle. The angle between the tower and the ground is formed by the guy wire.
90 ft
the answer is
It's pronounced 'GUY-yo.' That's guy, as in, "What a guy!" or "guy wire."
je poopey from family guy
Nobody really needed him he just thought that so that he would think he was a good guy. Well he is a good guy but nobody needed him
He writes with it
It means a guy needed help
They do not have any supports for the shipping splits under the TS1 and TS4 were needed. I'm not sure what they are going to do. This came out at a Skanska called guy wire meeting. What a problem it's going to be to get the guy wires in. They sent us a roof top view with everything in it. Looks pretty neat but makes the guy wire stuff look impossible. Our PE has this and is looking to see what can be done. Just trying to keep you in the loop.
A guy wire anchor is used to secure the guy wire to the ground or structure. It helps provide stability and support to the structure, particularly in situations where the structure needs to withstand tension or lateral forces.
The simplest way is to ask him.
The guy wire forms a right triangle with the pole and the ground. Using the Pythagorean theorem (a^2 + b^2 = c^2), we can calculate the length of the guy wire. In this case, a = 10 ft, b = 15 ft, so the length of the guy wire (c) is √(10^2 + 15^2) = √(100 + 225) = √325 ≈ 18.03 ft.
You determine that by how you respond.
The guy wire, pole, and ground form a right triangle. Using the Pythagorean theorem (a^2 + b^2 = c^2), where a = 4m and b = 6m, we can solve for the length of the guy wire (c). Thus, c = √(4^2 + 6^2) = √(16 + 36) = √52 meters, or approximately 7.2 meters long.