No, LED lights typically have a higher lumen efficiency than traditional incandescent bulbs, but they are not 100 percent efficient. LED lights can convert more of the electricity they consume into visible light, resulting in higher lumen output for the same amount of power. However, some energy is still lost as heat.
This question is ill posed. Lumen is a unit of measure for how much light comes from the lamp Watt is a unit of measure for how much energy is used by the lamp If the question were; "Which is brighter, a 2000 lumen bulb or a 1500 lumen bulb?" then the answer would be: The 2000 lumen bulb. I think the relation ship between lumen and watt is something like: Incandecent bulbs are 15w/lumen Flourecent bulbs use 40w/lumen LED bulbs are 70w/lumen The way to show the watt and lumen relationship is usually lumens (amount of light) per watt (energy consumption). This is like gas in your car (Miles or KM per Gallon or Liter). Incandescent bulbs have a maximum luminosity of 52 lumens/watt. Fluorescent bulbs range from 46 lumens/watt (CFL) to 100 lumens/watt (T5 and T8 tubes) LED bulbs range from 29 lumens/watt (older, low efficiency) to 100+ (XCree) and they are getting better.
Brightness is measured in lumens so the bulb has a brightness of 100 lumens. The electrical power the bulb uses is measured in watts. The efficiency of a bulb is expressed in the number of lumens produced per watt of electric power.
The percent efficiency would be calculated by dividing the useful output by the total input energy and multiplying by 100. In this case, the useful output is 6W (light energy produced) and the total input is 60W (electricity consumed). Therefore, the efficiency would be (6/60) * 100 = 10%.
The efficiency of an electric furnace can vary but typically ranges from 95-100%. This means that most of the electricity used is converted into heat, with very little wasted energy. Regular maintenance and proper installation can help optimize the efficiency of an electric furnace.
Because semiconductors such as silicon are indirect bandgap semiconductors, so some of the light energy is wasted as lattice vibrations (phonons).
nothing has 100% efficiency.
No. Nothing mechanical can ever have a 100% efficiency by any physical evaluation.
why is the efficiency of a calorimeter less than 100%
If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.
The laws of thermodynamics imply that there will always be some loss of efficiency.
"Unity"
(work out/work in) x 100
Because there is always going to be friction, the efficiency of any machine will always be less then 100 percent.
The efficiency of the machine can be calculated by dividing the useful work output by the total input energy and multiplying by 100. In this case, the efficiency would be (35/100) * 100 = 35%.
A machine with 100 percent mechanical efficiency would be called an ideal machine, as it would have no energy losses due to friction, heat, or other inefficiencies.
Work done = (force * distance)>Efficiency (%) = (Work done output / Work done input) * 100
100*80/100 = 80%