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To determine the amount of chromium (III) oxide (Cr2O3) needed to produce 421 g of chromium (III) sulfide (Cr2S3), you need to consider the molar ratio of the reactants. The molar mass of Cr2S3 is 256.16 g/mol, and Cr2O3 has a molar mass of 151.99 g/mol. First, calculate the moles of Cr2S3 produced from 421 g. Then, use the molar ratio from the balanced chemical equation to find the moles of Cr2O3 needed, and convert this to grams.

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Q: Chromium iii oxide reacts with hydrogen sulfide h2s gas to form chromium iii sulfide and water how many grams of cr2o3 are required to produce 421 g of cr2s3?
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