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An object of a mass of 2.5 kg is thrown upwards with an initial speed of 39 ms How fast is the object traveling just before it hits the ground Assume that there is no air resistance?
Almesserli22
Assumptions:
1) You throw it straight up. No angle, nothing.
2) Answers.com removed your punctuation, thus you meant initial speed of 39 m/s
3) No air resistance
4) Your "throw" begins at the ground (meaning you're not counting the height of the person)
Answer = 39 m/s
Reasoning: With nothing but the acceleration of gravity to slow it, it will slow to a stop, then accelerate and return along the same path. With no resistance, it will accelerate to the same velocity as its initial velocity by the time it reaches the point of origin.
Fun Fact: Feel free to try this. I recommend using a hackey-sack and laying on your back while you throw upward.
Wiki User
∙ 14y ago
The final speed of the object just before it hits the ground can be calculated using the kinematic equation: v^2 = u^2 + 2as. Given that the initial speed (u) is 39 m/s, acceleration due to gravity (a) is -9.81 m/s^2, and the object travels a vertical distance (s) before hitting the ground, you can solve for v.
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