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According to Hubble's law with H0 equals 22km per s per million-light-years what is the recessional velocity of a galaxy at a distance of 1 billion light years?
Wiki User
∙ 14y ago
Since a billion light years is 1000 times a million, that means that you simply have to multiply 1000 x 22 km/sec, with a result of 22,000 km/sec.
Wiki User
∙ 14y ago
The recessional velocity of a galaxy at a distance of 1 billion light years would be calculated using Hubble's Law by multiplying the Hubble constant (H0) with the distance.
Recessional velocity = H0 x distance = 22 km/s/Mly x 1,000 Mly = 22,000 km/s
Therefore, the recessional velocity of a galaxy at 1 billion light years would be 22,000 km/s.
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When do two different distance-time graphs have matching velocity-time graphs?
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What is the time when you are given velocity and distance?
Velocity is in distance/time, so multiplied by 1/distance would give you 1/time. Hope this helps!
How do you calculate distance when given velocity and weight?
To calculate distance with velocity and weight, you can use the equation for work: Work = Force x Distance. The force can be calculated by multiplying the weight with gravity. Velocity can then be used to determine the time it takes for the object to travel that distance using the equation Distance = Velocity x Time.
What kind of mathematical relationship exists between velocity and distance?
Velocity is the rate of change of distance over time. This relationship is described by the equation velocity = distance/time, where velocity is measured in units like meters per second, distance is measured in units like meters, and time is measured in units like seconds. As velocity increases, the distance covered in a given amount of time also increases.
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
What is the recessional velocity of a galaxy at a distance of 200 Mpc?
The recession velocity of a galaxy at a distance of 200 Mpc (mega-parsecs) would depend on Hubble's Law and the rate of expansion of the universe. For a rough estimate, assuming a Hubble constant of 70 km/s/Mpc, the recession velocity would be around 14,000 km/s.
If you know the velocity and the distance but not the time which way do you divide velocity divided by distance or distance divided by velocity?
To find the time when you know the distance and velocity but not the time, you should divide distance by velocity. This is because time equals distance divided by velocity (time = distance/velocity).
Equations for velocity?
Velocity = distance / unit of time
How do you find distance when you know the time and velocity?
Simple, velocity = distance by time ,which probably means distance = velocity X times.
How do you find time when you know the distance and the velocity?
distance/velocity = time
Why does velocity not depend on distance?
Velocity is the rate at which an object changes its position, regardless of the distance it has traveled. Velocity considers both speed and direction, so a change in direction can affect velocity even if distance remains constant. Distance is the total length of the path traveled, whereas velocity focuses on the rate of change in position.
What is the formula for uniform velocity?
The formula for uniform velocity is: Velocity = Distance / Time.
The distance between speed and velocity is that velocity includes?
Velocity includes direction. And it's the 'difference', not the 'distance'.
How do you measure Velocity-?
velocity = distance travelled/time taken to travel that distance
How do you solve for Velocity?
velocity = distance/time
What is the formula to velocity?
Velocity is distance / time
Is distance directly proportional to velocity?
Distance Traveled is directly proportional to velocity. This is because velocity is the change in position over a period of time. The greater the velocity, the greater the distance traveled. For you calculus junkies, integrate velocity to get displacement.
