A gas sample has a volume of 128 mL at 90.7 kPa What will its volume be at 113 kPa?

Answer 1

percentage change: 113-90.7/90.7= 22.3/90.7=(0.24....x 128)+128=159.47mL

Answer 2

Using Boyle's Law, we can solve for the new volume of the gas sample: ( \frac{P_1 \cdot V_1}{P_2} = V_2 ). Plugging in the values, we get ( \frac{90.7 , \text{kPa} \cdot 128 , \text{mL}}{113 , \text{kPa}} \approx 102.8 , \text{mL} ).