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A brass wire is to withstand a tensile force of 280 N without breaking What minimum diameter must the wire have?
Wiki User
∙ 14y ago
The minimum diameter of the brass wire can be calculated using the formula for tensile stress: stress = Force / (pi * radius^2). Rearranging the formula to solve for the radius, we get radius = sqrt(Force / (stress * pi)). Plugging in the values, with force = 280 N and stress for brass = 110 x 10^6 N/m^2, we find that the minimum radius of the wire should be approximately 2.35 mm. Therefore, the minimum diameter required would be twice the radius, which is about 4.7 mm.
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