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A block of mass M is pulled with a rope on a frictionless surface If a force P is applied at the free end of the rope what will be the force exerted by the rope on the block if the mass of rope is m?

Equation#1: Force = mass * acceleration

The force P pulls a total mass of (M + m) accelerating both masses at the same rate.

Equation #2: P = (M + m) * a

Equation #3: a = P ÷ (M + m)

At the point where the rope is attached to the block, the block of mass M feels a force making it accelerate at a rate of a = P ÷ (M + m).

The force required to make at block of mass M accelerate at a rate of a = P ÷ (M + m) can be determined by equation #4.

Equation #4: F of block = mass of block * [P ÷ (M + m)].

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1mo ago

The force exerted by the rope on the block will be equal to the applied force P. This is due to the fact that the rope is assumed to be ideal and massless, transmitting the force applied at one end without any loss. Therefore, the force exerted by the rope on the block will be equal to the force applied by the person pulling the rope.

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Q: A block of mass M is pulled with a rope on a frictionless surface If a force P is applied at the free end of the rope what will be the force exerted by the rope on the block if the mass of rope is m?
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