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The answer is Al2Se3

... dont ask me why or how but thats what my online qiuz said was correct so thats the right answer!

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12y ago
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1mo ago

The molar mass of aluminum is 26.98 g/mol, and the molar mass of selenium is 78.96 g/mol. Using the given masses, we find that there are 0.270 moles of aluminum and 0.499 moles of selenium in the compound. Dividing by the smallest number of moles (0.270) gives us the empirical formula Al2Se3.

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Q: A 7.300 gram sample of aluminum was quantitatively combined with a sample of selenium to form a compound The compound weighed 39.35 grams What is the empirical formula for this compound?
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