mass Fe * Specific heat Fe* T=Q Q/( Specific Heat water*mass water)= temp change of water so... 4kg(.450 kJ/kg*C)(250C)= 3kg(4.184)T T=35.85 C That help?
To find the change in temperature of the water, you can use the principle of conservation of energy, specifically the equation (m_1c_1(T_1 - T_f) = m_2c_2(T_f - T_2)). Given that the iron bar and water reach thermal equilibrium, you can solve for the final temperature (Tf) of the system. Once you calculate Tf, you can find the change in temperature of the water by subtracting the initial temperature of the water from Tf.
The answer is 1,83 moles.
To find the final temperature of the water, we can use the principle of conservation of energy, which states that the total energy of the system remains constant. By using the formula: (mass1 * specific heat1 * change in temperature1) = (mass2 * specific heat2 * change in temperature2), we can calculate the final temperature to be approximately 13.3 degrees Celsius.
303K refers to a temperature of 303 Kelvin, which is equivalent to approximately 30 degrees Celsius. "Volume at 25L" typically means the volume of a substance is 25 liters, indicating the amount of space that substance occupies.
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
At NTP (standard temperature and pressure), which is 0 degrees Celsius and 1 atm pressure, the volume occupied by 1 gram of helium would be approximately 22.4 liters. This value is based on the ideal gas law and the molar mass of helium.
100 degrees Celsius
To raise the temperature of 1 liter of water by 1 degree Celsius, it requires 1 kilocalorie. Therefore, to burn 330 kilocalories and heat cold water from 4 degrees Celsius to 37 degrees Celsius, you would need to drink 33 liters of cold water.
50 grams and 96 degrees Celsius are not measurements of volume. The options provided are not related to volume either; 148 meters is a measurement of length and 259 liters is a measurement of volume.
The answer is 1,83 moles.
About 0.9kg (900g)
A gram of oxygen is equivalent to approximately 0.56 liters at standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere of pressure.
Using the ideal gas law, (PV = nRT), we can solve for the final temperature using the initial conditions and new pressure. Rearranging the equation to solve for T, we get (T = (P2/P1) * T1), where T1 is the initial temperature. Substituting the values, we find the final temperature to be 80 degrees Celsius.
To raise the temperature of 1000 liters of water by 10 degrees Celsius, you would require approximately 239 kilowatt-hours of energy. This can be calculated using the specific heat capacity of water and the formula for calculating energy required for temperature change.
If 2.2 liters of gas is inhaled at 18 degrees Celsius and is heated to 38 degrees Celsius in the lungs, what is the new volume of the gas
Standard temperature and pressure (STP) for oxygen is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals). At STP, one mole of oxygen gas occupies a volume of 22.4 liters.
Meters, liters and degrees Celsius are used by the world.
To find the final temperature of the water, we can use the principle of conservation of energy, which states that the total energy of the system remains constant. By using the formula: (mass1 * specific heat1 * change in temperature1) = (mass2 * specific heat2 * change in temperature2), we can calculate the final temperature to be approximately 13.3 degrees Celsius.