The short answer is that the circuit will have a very high level of current or the maximum amount that the voltage source can provide. Long Answer When analyzing electrical circuits the resistance of the wires is often ignored because it is so small and it makes the calculations easier. In reality all wires or conductors have a certain amount of resistance that affects the circuit. This makes it impossible to have a circuit without any resistance. Following that, Ohm's law can be used to describe what will happen in any circuit. Ohm's Law: Voltage = Current * Resistance or V = I * R Example: Very simple circuit A 12 volt car battery has a wire connecting the positive and negative terminals directly. The resistance of the wire is .001 ohms. What is the current? I = V/R I = 6volts / 0.001 ohms I = 6000 amps Of course, a car battery cannot provide this much current, so the maximum amount that it provide can will flow through the wire. Also, the wire will surely burn up from the high levels of current.
The circuit for high speed involves the relay to be closed. On a 1995 Chevy Pickup it is located behind the glove compartment. The lower speeds use a fan resistor pack for the different speeds. The voltage supplied to the resistor pack is usually a 25 amp inside fuse. The high speed circuit is supplied by a constant 12 volts that turns on the fan when the relay is energized. The voltage for the high speed circuit comes from a fuse under the hood. Usually a 50 amp. If all fuses are good then there might be a fusable link in the wire somewhere.
I had this happen to me and it was the resister connectors , could be the resistor itself, 92 had it mounted on left front fender near top, it gets weather in on it and the wires corrode in their covers.
The opposition of a body or substance to current passing through it, resulting in a change of electrical energy into heat or another form of energy. So it could be any substance. From 68.191.13.211. Now would someone out there add to what you have sen so far. Then we will all be more aware of the exact nature of the resistance.
you would die
Its very easy, go to your local GM parts counter and order a pigtail for the blower motor resistor harness, all you need to do is cut and connect the appropriate wires together and youll be all set.
It is used to vary the voltage/current flow in a circuit.
Resistor have a definite function in circuits and because every resistor disspates power, it is not included in the circuit without good reason. Some smoke detectors have electronic circuits in them, and these would have resistors, but it is not possible to be more specific.
a battery and a resistor connected together.
If the resistor is removed from the circuit, the total resistance in the circuit decreases. This causes the total current in the circuit to increase, which would result in an increase in the ammeter reading.
The total current in the circuit will decrease.
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
In order to answer that, one would need to know what the circuit is designed to do (so that he would know how to tell when the circuit is "working"), and would also need to see the schematic diagram, in order to know exactly how the fixed resistor and the thermistor are configured in the circuit, and what other components are involved. Consider . . . If I came up to you on the street, or even for that matter in an Engineering lab, and I said to you "I've got a circuit with a coil and a resistor in it. Will it work if the impedance of the coil is greater than the resistance of the resistor ?", you would most certainly find yourself at a loss, just as I do when I read your question.
No. It will not serve its intended purpose.
This is an overcurrent condition, correct? The real answer is, "well, it's not SUPPOSED to open!" Which is true--if the emitter resistor opens, the smoke (which, as we all know, is the thing that makes electrical devices work) gets out and the circuit stops working. If you're in an overcurrent condition sufficient to destroy parts and you don't lose the resistor, the transistor being serviced by the emitter resistor is destroyed. Having said that, the circuit should be designed so the bias current is low enough that it won't destroy parts.
Too much power is likely to burn out the bulb's filament, or shorten the bulb's life. A resistor of suitable rating, placed within the circuit, would help reduce the voltage to a more suitable level
the circuit would not be complete. the lightbulb would not light or the buzzer would not buzz
There will be no change, because it is a parallel circuit.