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Q: When do you use D2?
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Here~ D2 D2 D2 B D2 C2 B A C2 C2 C2 A C2 B A G D2 D2 D2 G G A B C2 C2 C2 C2 D2 C2 B A G D2 D2 D2 B D2 D2 D2 B D2 D2 D2 E2 D2 D2 B C2 C2 C2 A C2 C2 C2 A C2 C2 C2 B2 C2 B A G


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Let D represent the length of the diagonal and A the area. Suppose the sides are L and B. Then A = L*B and by Pythagoras, D2 = L2 + B2 These two equations need to be solved as simultaneous equations to get the values of L and B. One way is to use the following identities: (L + B)2 = L2 + 2LB + B2 = D2 + 2A so that L + B = sqrt(D2 + 2A) and (L - B)2 = L2 - 2LB + B2 = D2 - 2A so that L - B = sqrt(D2 - 2A) which then give 2L = sqrt(D2 + 2A) + sqrt(D2 - 2A) and 2B = sqrt(D2 + 2A) - sqrt(D2 - 2A)


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