Disconnecting a wire from a battery would break the circuit. If the battery was powering a bulb, the lamp would go out.
Nothing much will happen except the same bulb will not blow..
An example of a closed electrical circuit would be a battery to a light bulb, the only source of power being the battery and no other input from an outside source. Like video cameras in a store they would be considered a closed circuit surveillance system so long as the signals stay inside the store and don't leave to a remote location.
A D cell battery supplies nominally 1.5V. Connecting a 6V supply in it's place would supply an extra 4.5V and could potentially damage the circuit components.
A battery or eletrical generator would do that.AnswerYour question should be rephrased. You do not 'give power' to a circuit. 'Power' is simply a rate -the rate of doing work.
You would short out the battery. If it was a car battery capable of 300 amps and the wire was big enough, the battery could explode.
If the bulb is removed from its holder, the circuit will be open, breaking the flow of electricity. This will result in the current being unable to pass through the circuit and the bulb will not light up as a result.
would discharge in 18 hours
Adding one more battery to a parallel circuit of two light bulbs would increase the voltage across the entire circuit. This would cause both light bulbs to shine more brightly as they receive more power. It will not affect the current flowing through the circuit but will boost the overall energy provided to the circuit.
V = IR, so if you double the voltage without changing the resistance, the current will also double.
A well designed circuit should be able to operate over a range of voltages, not just at one voltage. Especially a circuit which is intended to be powered by a battery. As the battery starts to get used up, and the voltage drops, you want the circuit to operate as planned.
Nothing. The reason a circuit works is that there is an imbalance between the positive and negative (cathode and anode) ends of the battery. two positive ends wouldn't move anything.
Disconnecting a wire from a battery would break the circuit. If the battery was powering a bulb, the lamp would go out.
Adding a seound battery to a series circuit will increase the voltage, and require less current to keep the lights (if there are any on) as bright. Say you have a 6v battery, then you add another 6v battery. the voltage of the circuit would be 12v
The circuit will de-energize.
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.
Since load current is determined by dividing the supply voltage by the resistance (for d.c., or impedance for a.c.) of the load, a short circuit would theoretically result in an infinite supply current. This is because a short circuit has, theoretically, zero resistance. In practice, however, the current would be cut off by the operation of an overcurrent protective device -such as a fuse or circuit breaker- which would disconnect the short circuit from the supply voltage. A worst-case scenario could occur should you short-circuit a car battery with, say, a spanner (wrench). With no fuse to protect the battery, the resulting short-circuit current, if sustained, may be high enough to cause catastrophic damage to the battery.