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The maximum base thickness in a BJT is dependent on a number of variables and parameters (or call them "constraints").

You could create a base region with thickness ranging from a few layers of atoms up to the point where the "base" region responds to the models of bulk semiconductor by messing with the process parameters. But why?

If the base is too thick then with the transistor biased into the 'active' region (i.e., B-E junction forward biased & B-C junction reverse biased), the transistor 'alpha' (the ratio of carriers collected by BC to those generated in BE) will be hopelessly low and the transistor will not exhibit the high current gain that you expect from BJTs.

That's because a thick base provides too much opportunity for large numbers of forward current charge carriers to be recaptured by the crystal matrix or lost to the collector current in other ways.

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Q: What is the maximum base thickness in a BJT transistor?
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Bipolar transistor current gain is also called "Beta," or the h-parameter "hfe." beta = current_out / current_in The beta of a BJT is mostly determined by the thickness of the Base region, and by the excess doping in the Emitter relative to the Base. A thin Base and a heavily-doped Emitter leads to a high value for current gain. In a BJT, beta = Ic / Ib In a FET, beta is usually taken as infinity, since no current flows in or out of the gate. Beta is an impirical number. It means nothing unless the Ic is known or the load. It can have a beta from 1000 to 10 it all depends on the load.


What is the main advantage of an fet transistor over a bjt transistor?

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Why use a npn transistor in a common emitter bjt single stage amplifier circuit?

You can use an npn or a pnp bjt in a common emitter amplifier circuit. The decision of which one to use is based on whether you want the collector and base to be more positive (npn) or more negative (pnp) than the emitter.


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