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The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.

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Q: What force or forces are acting on the crate?
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A crate is at rest on the ground what force or forces are acting on the crate?

The weight of the crate is acting downward on the ground and the ground is exerting a force equal to the weight of the crate upward on the crate.


What is the net force acting on a sliding crate?

The net force on a sliding crate is the vector sum of all forces acting on the crate. It is the force that is causing the crate to accelerate or decelerate. If all forces are balanced, the net force will be zero and the crate will move at a constant velocity.


If you push a crate with a force of 100 N and it slides at a constant velocity how much is the friction acting on the crate?

If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.


What do you have to do get forces acting on an object to get you net force?

a girl and a boy are pulling heavy crate at the same time with 10 units of force each . what is the net force acting on ythe object?


Pull horizontally on a crate with a force of 140 N and it slides across the floor in a dynamic equilibrium How much friction is acting on the crate?

If the crate is in dynamic equilibrium, the frictional force acting on it is equal in magnitude but opposite in direction to the applied force. Therefore, the frictional force acting on the crate is also 140 N.


When you push on a crate with a force of 10n to the right and your frined pushes on the crtate with a force of 25 n to the left which way will the crate move and what is the net force of the crate?

The crate will move to the left because the force to the left (25N) is greater than the force to the right (10N). The net force acting on the crate is the difference between the two forces: 25N (left) - 10N (right) = 15N to the left.


What is the force of friction acting on a crate that slides across the floor?

The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.


If we push a crate at a constant velocity how do we know how much friction acts on the crate compared to our pushing force?

If the crate is moving at a constant velocity, then the force of friction acting on the crate is equal in magnitude and opposite in direction to the force you are applying to push the crate. This means that the force you apply to push the crate is balancing out the force of friction acting against it. By measuring the force you are exerting and observing the constant velocity of the crate, you can infer the magnitude of the friction force.


A 1500 N crate is being pushed across a level floor at a constant speed. What will be the acceleration of the crate?

The acceleration of the crate will be zero since it is moving at a constant speed. This means that the net force acting on the crate is zero, so the forces pushing it forward are balanced by the forces resisting its motion.


What is the force of friction when a crate slides across the floor?

The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.


If a crate is stationary on an incline does it mean that it is in the state of equilibrium?

No, the crate being stationary on an incline does not necessarily mean it is in equilibrium. Equilibrium requires not only that the crate is stationary but also that the forces acting on it are balanced. Without knowing the exact forces acting on the crate, we cannot conclude that it is in equilibrium.


What is the net of force acting on the object when a boy and a girl are pulling a heavy crate at the same time with 10 units of force each?

The net force on the crate would be 10 units (force applied by the boy) - 10 units (force applied by the girl) = 0 units. Since the forces are in opposite directions, they cancel each other out, resulting in a net force of zero.