You use a combination of Ohm's law ( V = I * R ) and the power formula ( P = V * I ).Substituting you get: P = ( I * R ) * I = I**2 * RDividing both sides by R you get: P / R = I**2 * R / R = I**2Taking the square root of both sides you get: SQRT( P / R) = ISwapping sides of the equals sign you get: I = SQRT( P / R )Thus the maximum current can be found using the equation I = SQRT( P / R ).
it means a situation that needs law and order if that makes sense such as in a court house u need order if you committed a crime you need to be punished by law if you committed a crime and is in court then u r in law and order situation
V = I * R V = voltage I = curernt R = resistance
Yes you can... and its handy for solving Kirchoff's law mesh equations[V] = [R].[I] (that's [R].[I], remember order is important when multiplying matrices)
Nothing. If I is current, V is voltage, and R is resistance, then V=I*R and V*I=P, where P is power.
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R. P. Gadd has written: 'Peerage law' -- subject(s): Peerage, Law and legislation
Law of Detachment also known as Modus Ponens (MP) says that if p=>q is true and p is true, then q must be true. The Law of Syllogism is also called the Law of Transitivity and states: if p=>q and q=>r are both true, then p=>r is true.
R. P. Sethi has written: 'The Hindu marriage act, 1955' -- subject- s -: Marriage - Hindu law -, Marriage law
T= Temperature P= Pulse R= Respiration
........V I = ------ ........R I = Ohm's Law V = Voltage R = Resistance (Ignore the dots they stop V and R from moving to the left!)
Joule's law, which states the relationship between electrical power, current, and resistance, is derived from Ohm's law, P = IV, and the formula for electrical power, P = I^2R. By substituting I = V/R from Ohm's law into the power formula, you can derive Joule's law as P = V^2/R.
Combination Formula ProofGENERIC:Let C(n,r) be the number of ways to generate unordered combinationsThe number of ordered combinations (i.e. r-permutations) is P(n,r)The number of ways to order a single one of those r-permutations P(r,r)The total number of unordered combinations is the total number of ordered combinations (i.e. r-permutations) divided by the number of ways to order each combinationThus, C(n,r) = P(n,r)/P(r,r) = [n!/(n-r)!]/r!/(r-r)!] = n!/r!(n(n-r)!SPECIFIC:Let C(52,5) be the number of ways to generate unordered poker handsThe number of ordered poker hands is P(52,5) = 311,875,200The number of ways to order a single poker hand is P(5,5) = 5! = 120The total number of unordered poker hands is the total number of ordered hands divided by the number of ways to order each handThus, C(52,5) = P(52,5)/P(5,5)
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
p = r - c r - c = p r - c - r = p - r -(-c) = -(p) c = -p
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