Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.
Consider t resistors with same Ohmic values. If they are in series total resistance Rt = R1 + R2. if they are in parallel then total resistance Rt = 1/R1 + 1/R2. Series connection will have higher resistance.
total resistance of a parallel connection network of resisters is equals the total resistance divided by one. 1/total R = 1/R1+1/R2+1/R3+................+1/RN since we get 1/total R from the above formula, to get total resistance (total R) just reciprocate the answer. secondly, if u have only two resistors connected in parallel say R1 & R2, then total Resistance total R=(R1*R2 )/R1+R2 inform.mayaprasad@gmail.com
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.
The total resistance in a series circuit is determined by adding (summing) the individual resistances of each component in the circuit.
No, the total resistance increases.
Ohm's law states that the current in a circuit is inversely proportional to the circuit resistance. There is a single path for current in a series circuit. The amount of current is determined by the total resistance of the circuit and the applied voltage.
You raise the total resistance by that amount if added in series to a circuit. If you add them in parallel to a circuit then that total resistance will be less than the total of the added circuit.
When more light bulbs are added in parallel to a circuit, the total resistance of the circuit decreases. This is because in a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. More paths for current to flow mean less overall resistance in the circuit.
No, series parallel, as it implies has components of the circuit configured in both series and parallel. This is typically done to achieve a desired resistance in the circuit. A parallel circuit is a circuit that only has the components hooked in parallel, which would result in a lower total resistance in the circuit than if the components were hooked up in a series parallel configuration.
You add up the currents in each branch. The current in each branch is just (voltage acrossd the parallel circuit)/(resistance of that branch) . ==================================== If you'd rather do it the more elegant way, then . . . -- Write down the reciprocal of the resistance of each branch. -- Add up the reciprocals. -- Take the reciprocal of the sum. The number you have now is the 'effective' resistance of the parallel circuit ... the single resistance that it looks like electrically. -- The total current through the parallel circuit is (voltage acrossd the parallel circuit)/(effective resistace of the parallel circuit) .
The total effecive resistance of several individual resistances in parallel is less than the smallest individual resistance, so in that sense I guess you'd have to say that the lowest resistance 'dominates' the character of the whole parallel circuit.
D. The total resistance is equal to the lowest resistance in the circuit
no
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