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Addition:VCC, VEE, VBB are grounded voltages of a collector, emitter, and base, respectively, on a transistor.The reason this letter is doubled is to represent a voltage connected between ground and the collector(/emitter/base). Since there is no notation to identify ground (0), the corresponding letter is doubled (IEEE standard). One way to read this notation is as the 'grounded voltage of the collector/emitter/base."AnswerThe representations like Vcc ,Vbb , Vee etc are just a part a nomenclature.it is used to represent the voltage given to the nodes of the transistorin this nomenclature voltage given to the ends are denoted by the letter v for the supply voltage and 2 times the first letter of emitter collector or the base where the voltage is given
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- The ratio of the dc collector current (IC) to the dc base current (IB) is thedc beta (bDC).- bDC is called the gainof a transistor:bDC = IC/IB- Typical values of bDC range from less than 20 to 200 or higher.- bDC is usually designated as an equivalent hybrid (h)parameter:hFE = bDC- The ratio of the collector current (IC) to the dc emitter current (IE) is the dc alpha (aDC). This is a less-used parameter than beta.aDC = IC/IE- Typical values range from 0.95 to 0.99 or greater.- aDC is always less than 1.- This is because IC is always slightly less than IE by the amount of IB.- From graph above we can see that there are 6 important parameters to be considered:i) IB: dc base current.ii) IE: dc emitter current.iii) IC: dc collector current.iv) VBE: dc voltage at base with respect to emitter.v) VCB: dc voltage at collector with respect to base.vi) VCE: dc voltage at collector with respect to emitter.- VBB forward-biases the BE junction.- VCC reverse-biases the BC junction.- When the BE junction is forward biased, it is like a forward biased diode:VBE ? 0.7 V- But it can be as high as 0.9 V (and is dependent on current). We will use 0.7 V from now on.- Emitter is at ground. Thus the voltage across RB isVR(B) = VBB- VBE- AlsoVR(B) = I­RRB- Or:I­RRB = VBB- VBE- Solving:IB = (VBB- VBE)/RB- Voltage at collector with respect to grounded emitter is:VCE = VCC - VR(C)- Since drop across RC is VR(C) = ICRC the voltage at the collector is also:VCE = VCC - ICRC- Where IC = bDCIB. Voltage across the reverse-biased collector-bias junction isVCB = VCE - VBEthank you
It might be if 'your' were 'my' because then it would contain all the letters of the English alphabet. Did you let the automatic question fixer change your question, and not catch it before posting? Yes it is a typewriter test it uses every letter in the alphabet another is "quick brown fox jumps over the lazy dog" His behavior was unusual at the bithday party because he ate too much sugar. djhfnbvcvx nbjn,h vccvgbcdhvbghjdcvhgdgfgfhhhhhhhhdfffffffffffffffffff aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbcccccccccccccccccccccccccccccccccccccccccccccccccccddddddddddddddddddddddddddddddeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeedfedhrwklj.nd vccbmncnbm ikjzzzzsgbjdfucxhdshfjksdhfkhjdhfkjhfhaqqqqqqqqq1234567890-=qwertyuiop[]]]]\asdfghjkl;'''''''zxcvbnm,./ Zxcvbnm,./asdfghjkl;'tiuyitkgh vbb mchrtdv nbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbujmgfvbujmhnk bv
NO. THE UNIVERSAL LAW STILL APPLIES -- ENERGY CANNOT BE CREATED NOR DESTROYED -- ONLY TRANSFORMED. Actually in amplifier we give it the Vcc,Vee,Vbb which is such value from which the gain of an amplifier cannot increase till the point of Vcc,it holds the law of conservation of energy but if gain reaches to Vcc then it is in cutoff region so,never the amplification process violate the law of conservation of energy Actually in amplifer we want the required phase shift+amount of required voltage from sources present so this is actually the use of amplifier that it enhances our strength over particular shape waveform and magnitude at required point