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∙ 14y ago674
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∙ 14y ago1111 1111 1111 1111 = 2^16 = 65536
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.
You get the largest number if you sort the digits, from largest to smallest.
It is a procedure for converting numerical data stored in information technology (electronic or optical) media to the decimal form that people are accustomed to using.
0.0000001
0.9999
65,535
1111 1111 1111 1111 = 2^16 = 65536
An N-bit integer holds 2N different values.For an unsigned integer, the range of values is 0..2N-1 thus.For a signed integer using 2s complement, the range is -2N-1..+2N-1-1.Therefore, the largest positive number that can be stored using 8 bits is 255.
Using the digits 12279, the largest number that can be represented is 97,221.
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
only one zero can be added using a decimal
Using a decimal, of course. All you need do is move the decimal point two places to the right.
The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.
If using the compressed format, where a byte holds two decimal digits (because only 4 bits are needed to make nine), so two bytes would be four decimal digits, the largest which is 9999.
It is a procedure for converting numerical data stored in information technology (electronic or optical) media to the decimal form that people are accustomed to using.