If you mean CI minus XLVIII then it is LIII because 101 minus 48 = 53
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If you mean as in Roman numerals CI - XLVIII then it is LIII
XL = 40 VIII = 8 XLVIII = 48
40, XL signifies 50 (L) minus 10 (X).
You would get the 40 using 50 minus 10 or XL. Two is represented with II, so that 42 is XLII.
In today's notation we would write it out as (VIII)CDLXXXIX = 8000+400+80+9 = 8489 But the Romans themselves probably wrote it out as L(VIII)DXXXVIII = minus 50 plus 8539 = 8489