forming a simultaenous equation where x+y=27 and x-y=3 you find that x=15 and y=12.
po12
45
27 and 13
The numbers are: 27 and 23
12 and 15
-27 and -2
3 and 9
35+27=62
27 and 81
12 and 15 have a sum of 27 and a difference of 3. Their LCM is 60.
27 and 13
The numbers are 27 and 23
The numbers are: 27 and 23
12 and 15
The answer is: 3
The numbers are 26 and 27.
x+y=40 + x-y=14 2x =54 x=27 y=13
The two numbers are... 12 & 15. The equation is... x equals y times 3
The numbers are: 7 and 20