n-4
n/4
The quotient when the square root of a number n is divided by two?
n/7
n/14
n-4
(n/4)2, where n is a number.
n/4
7 more than the quotient of a number n and 4 is 9
Let the number to be found is N. Use Order of Operations. So first do the quotient part: 'the quotient of a number and 6' means N/6. '4 more than' means 4 + N/6, and then it equals 40, so4 + N/6 = 40N/6 = 36N = 216
6 + (the quotient of a number and 4) =6 + (number ÷ 4)=6 + (N÷4) =⁶/₁ + ⁿ/₄ =²⁴/₄ + ⁿ/₄ =²⁴ⁿ/₄ =24n ÷ 4 =6n ÷ 1 =6n
4 + (x/3) >= x
Explanation: Quotient means that you divide something by another. Let's let n be the "number". Therefore, "a quotient of a number and 6" refers to n 6 or n รท 6 .
To solve this problem, we can set up the equation n = 7q + 4, where n is the unknown number, q is the quotient, and 4 is the remainder. Since the problem states that when n is divided by 7, the quotient is 3, we can substitute q = 3 into the equation to get n = 7(3) + 4 = 21 + 4 = 25. Therefore, the number in question is 25.
If the number is n, the quotient of the number and 12 is n/12.
Let n be the number then the quotient Q is given by :- Q = 4n³ ÷ (n² + 3) Performing long division gives Q = 4n - 12n/(n² + 3)
The quotient when the square root of a number n is divided by two?