Armstrong numbers are properly termed pluperfect digital invariant (PPDI) numbers. For an n-digit PPDI, the number is equal to the sum of each of its digits raised to the nth power. For example, for n = 3, there is 153 = 1^3 + 5^3 + 3^3 = 1 + 125 + 27. Incidentally, the mathematician G H Hardy stated that there are only four 3-digit PPDIs. He added that, although amusing, "there is nothing in them which appeals to the mathematician".Armstrong numbers are apparently named after a computing lecturer at the University of Rochester named Michael F Armstrong. In the mid 1960s he devised Armstrong numbers as an exercise for his students.
153/3 = 51The middle number is 51, so the numbers are...50, 51 and 52
yes for a number to be divisble by 3 you have to add the numbers together and see if you can divide it by 3 evenly 1+5+3= 9 9 can be divided by 3 evenly so that makes the number, 153 divisble by 3
There are 3 feet in one yard, so 153 feet is 51 yards
The sum of the digits of a multiple of 3 sum to a number that is itself divisible by 3. Example : 153 : 1 + 5 + 3 = 9 which is divisible by 3 so 153 is a multiple of 3. But : 206 : 2 + 0 + 6 = 8 shows that 206 is NOT a multiple of 3.
Well, sweetheart, Armstrong numbers, also known as narcissistic numbers, are numbers that are equal to the sum of their own digits raised to the power of the number of digits. In this case, the Armstrong numbers between 100 and 1000 are 153, 370, and 371. So, there you have it, darlin'. Hope that satisfies your curiosity.
/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }
No. To be a palindrome the number must read the same forwards as backwards. "153" is not the same number as "351" so this is not palindromic!
153 is an integer and so there is no sensible way of writing it as a fraction or mixed number.
The square root of 153 is approximately 12.369. This value is derived by finding the number which, when multiplied by itself, equals 153. In mathematical terms, the square root of 153 can be expressed as √153.
Armstrong numbers are properly termed pluperfect digital invariant (PPDI) numbers. For an n-digit PPDI, the number is equal to the sum of each of its digits raised to the nth power. For example, for n = 3, there is 153 = 1^3 + 5^3 + 3^3 = 1 + 125 + 27. Incidentally, the mathematician G H Hardy stated that there are only four 3-digit PPDIs. He added that, although amusing, "there is nothing in them which appeals to the mathematician".Armstrong numbers are apparently named after a computing lecturer at the University of Rochester named Michael F Armstrong. In the mid 1960s he devised Armstrong numbers as an exercise for his students.
153/3 = 51The middle number is 51, so the numbers are...50, 51 and 52
Armstrong was a famous jazz musician, he was called The King of Jazz, so he was called all over the world to play.
he is dead so there is no use on his phone number
To find the number that, when subtracted from 372, equals 153, you would perform the operation 372 - x = 153, where x represents the unknown number. To solve for x, you would subtract 153 from 372, resulting in x = 219. Therefore, 372 minus 219 equals 153.
Multiply it by a number which makes it into a whole number but also divide it by that same number, then simplify. Example: I pick 100, so 3.06*100/100 = 306/100. Now we can simplify 306/100 to 153/50, which is its most reduced form, so 3.06 = 153/50.
No because you can divide it by 3. E.g 153 divided by 3 = 51. So 153 is not prime.