b+b+b+c+c+c+c =3b+4c
2b + 2c or 2(b + c)
And how does this relate to coins?
A+c= 2a+b
Because there is no way to define the divisors, the equations cannot be evaluated.
b+b+b+c+c+c+c =3b+4c
b + b + b + c + c + c + c = 3b + 4c
It is impossible to give any decimal/numeric value if we are not given the values of at least one variable, so the answer is B + B + B + C + C + C.
sizeof (int) will tell you (in bytes). It's often 2, 4 or 8 bytes.
2b + 2c or 2(b + c)
And how does this relate to coins?
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
A+c= 2a+b
Try 'sizeof', it will return the size in bytes.
If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
Depending on context a megabyte (MB) can be defined as: a) 1,048,576 bytes (10242) for computer memory b) 1,000,000 bytes for computer storage. The IEEE Standards Board has determined that "Mega will mean 1,000,000" c) In rare cases it is used to mean 1000×1024 (1,024,000) bytes. So depending on context, 5205488 Bytes can equate to: a) 4.96 MB b) 5.20 MB c) 5.08 MB
If: a = b+c+d Then: c = a-b-d