While I'm tempted to tell you to do your own homework, this is intriguing enough that I'm willing to spend some time helping you to work it out.
First: by four digit palindromes that means numbers of the form ABBA.
A is constrained by "less than 5000". A can only be 0, 1, 2, 3, or 4, because otherwise ABBA would be greater than 5000 (the lowest possible ABBA number where A is 5 or greater is 5005 ... which is over 5000).
A is further constrained by "4 digit". It can't be 0, because by convention we don't write leading zeroes and then ABBA would only be a three digit number.
So A can be 1, 2, 3, or 4 (4 distinct possibilities).
There are no constraints on B. It can be any digit (including 0), which means there are 10 distinct possibilities.
Since once we specify both A and B we're done, that means there are (4 possibilities for A) x (10 possibilities for B) = 40 four-digit palindromes less than 5000.
There are 90 four-digit palindromes
There is 90 four digit palindromes.
There are no four-digit perfect squares that are palindromes.
There are 10 3-digit odd palindromes that are divisible by five.
9 of them.
There are 90 four-digit palindromes
There is 90 four digit palindromes.
There are 90 four-digit palindromes
There are no four-digit perfect squares that are palindromes.
There are 900 6-digit palindromes.
There are 10 3-digit odd palindromes that are divisible by five.
9 of them.
90 of them.
90
For there to be palindromes, each digit must be replicated. Therefore there are at most three distinct digits.If there are 3 pairs of different digits, then there are 6 palindromes. If there can be more duplicate digits, then there are 27 palindromes.
-4
8