There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
6
120
233 = 18 combinations.
3 items each in 3 categories gives 3*3*3 = 27 possible combinations.
There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.
You did not give us the set to work with...
6
Oh, dude, there are like 26 letters in the alphabet, right? So, for each position in a 3-letter combination, you have 26 choices. That means you'd have 26 choices for the first letter, 26 for the second, and 26 for the third. So, the total number of 3-letter combinations would be 26 x 26 x 26, which is... math.
676,000 but I don’t know why
The letter 'W'.
120
Gematriya is a numerical version of the Hebrew alphabet. For example, the first letter of the Hebrew Alphabet is the letter Aleph. This letter's Gematriya translation is 1 then the second letter Bet=2 Gimel= 3 Daled=4 Hey=5 etc. except there are many letters that do not correspond to the number in the alphabet that it is.
ABC
There are: 35C3 = 6545 combinations