Using the count() method:
I count 5, not counting the different orders that they are added as different ways. Here they are. If I missed some, then somebody else can add to it:3 + 3 + 3 + 3 + 1 = 133 + 3 + 5 + 1 + 1 = 135 + 5 + 1 + 1 + 17 + 3 + 1 + 1 + 19 + 1 + 1 + 1 + 1If you want to count different orders as unique, For #1, there are 4 additional ways (I wouldn't say that the different 3's are unique, so the 1 in each position).For #2, I count 13 additional ways. For # 3, I count 8 additional. For #4, I count 7 additional ways. And for #5, I count 4 additional ways. So that would be 36 additional ways, rearranging the orders, for a total of 41 ways.
3 or three...99, 100, 101...three '1's by my count
I can count to ten in French: Je peux compter jusqu'à dix en français.
1 2 3 4 5
1, 2, 3, 4... and so on ;-) 'Comte'
1-3-4-2... you can count that from either end, but 'officially' French cars count from the flywheel end (Source: www.aussiefrogs.com)
Using the count() method:
The French count today as day 1. 1 plus 14 equals 15.
3
1 2 3
count
Count on me
to count to ten is 'compter jusqu'Ã dix' in French.
I count 5, not counting the different orders that they are added as different ways. Here they are. If I missed some, then somebody else can add to it:3 + 3 + 3 + 3 + 1 = 133 + 3 + 5 + 1 + 1 = 135 + 5 + 1 + 1 + 17 + 3 + 1 + 1 + 19 + 1 + 1 + 1 + 1If you want to count different orders as unique, For #1, there are 4 additional ways (I wouldn't say that the different 3's are unique, so the 1 in each position).For #2, I count 13 additional ways. For # 3, I count 8 additional. For #4, I count 7 additional ways. And for #5, I count 4 additional ways. So that would be 36 additional ways, rearranging the orders, for a total of 41 ways.
1, 2, 3, 4
1, 2, 3...