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Q: How do you calculate BC to AD?
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How many years are there between 30 BC and 30 AD and why?

58 years are between 30 BC and AD 30. The first thing you need to remember is that there is no year 0; the year before AD 1 is 1 BC. So the years between 30 BC and AD 30 are... 29 BC, 28 BC, 27 BC, ..., 2 BC, 1 BC, AD1, AD 2, ..., AD 27, AD 28, AD 29 29 BC through 1 BC is 29 years, and AD 1 through AD 29 is 29 years. 29 years + 29 years = 58 years


What is mean AD AND BC?

BC = Before Christ. AD = Anno Domini (latin) the year of Christ's birth.


Can you always find another fraction in between ant two fractions why?

Yes. The simple answer is that rational fractions are infinitely dense. A longer proof follows:Suppose you have two fractions a/b and c/d where a, b, c and d are integers and b, d are positive integers.Without loss of generality, assume a/b < c/d.The inequality implies that ad < bc so that bc-ad>0 . . . . . . . . . . . . . . . . . . . (I)Consider (ad + bc)/(2bd)Then (ad+bc)/2bd - a/b = (ad+bc)/2bd - 2ad/2bd = (bc-ad)/2bdBy definition, b and d are positive so bd is positive and by result (I), the numerator is positive.That is to say, (ad+bc)/2bd - a/b > 0 or (ad+bc)/2bd > a/b.Similarly, by considering c/d - (ad+bc)/2bd is can be shown that c/d > (ad+bc)/2bd.Combining these results,a/b < (ad+bc)/2bd < c/d.


How is a plus b over a minus b equals c plus d over c minus d?

(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c


What do you do after cross multiplying when comparing fractions with unlike denominators?

Suppose the two fractions are a/b and c/d ad that b, d &gt; 0. Then cross multiplication gives ad and bc. If ad &gt; bc then a/b &gt; c/d, If ad = bc then a/b = c/d, and If ad &lt; bc then a/b &lt; c/d