Let's say that s is the total number of students, b is the number of boys, g is the total number of girls, n is the number of non-blonde girls, and e is the number if blonde girls. We know that s = b + g, b = g, g = n + e, e = g/3, and n = 10. Substituting for b in the first equation gives us s = g + g = 2g Then we substitute for n and e in the third equation and solve for g: g = g/3 + 10 g - g/3 = 10 g - (1/3)g = 10 (2/3)g = 10 g = 10 x (3/2) = 15 Finally, solve for s: s = 2g = 2 x 15 = 30
-1 is the G N I
n + 13 = 21. n = 21 - 13
6/100 X n = 21 .06 X n = 21 n = 21/.06 = 350
a b d e f F g G j J k L m n N p P q Q r R s S t u y z Z
There are 21 "o" characters in the phrase "21 o s in a g."
A-s-s-i-g-n-i-n-g.
N. G. Polite s has written: 'Laographika symmeikta'
E E-G--J---N----S-----Y E (F) G (HI) J (KLM) N (OPQR) S (TUVWX) Y Thats how i figured it out ^^^
Twelfth Regiment N-G-S-N-Y- - 1898 was released on: USA: April 1898
Eighth Regiment N-G-S-N-Y- - 1899 was released on: USA: June 1899
7th Regiment N-G-S-N-Y- - 1897 was released on: USA: March 1897
G. S. Maddala was born on 1933-05-21.
n i g g e r s
21 gays in your swimming pool
21 shillings in a Guinea
n i g g a s