$arr=array(2,5,4,6,7,8,1); for($i=0;$i<count($arr);$i++) { for($j=$i;$j<count($arr);$j++) { if($arr[$i] > $arr[$j]) { $temp=$arr[$i]; $arr[$i]=$arr[$j]; $arr[$j]=$temp; } } }
No arr refers to address of array &arr refers address of address of array but compiler treats arr and & arr, so even you place arr and & arr no error only warnings will be displayed.
Yes, 'ARR' and 'ARR' are the same for char20. Whatever it means.
for example:int arr[3];arr[0] = 1; /* ok */arr[1] = 2; /* ok */arr[2] = 0; /* ok */arr[3] = -1; /* wrong */arr[-1] = -3; /* wrong */
ways of getting 14 1,1,6,6 6 arrangements (1,6,1,6; 1,6,6,1; 1,1,6,6; 6,6,1,1; 6,1,6,1; 6,1,1,6) 1,2,5,6 24 arr. 1,3,4,6 24 arr. 1,3,5,5 12 arr. 1,4,4,5 12 arr. 2,2,4,6 12 arr. 2,2,5,5 6 arr. 2,3,3,6 12 arr. 2,3,4,5 24 arr. 2,4,4,4 4 arr. 3,3,3,5 4 arr. 3,3,4,4 6 arr. Total: 146 146*(1/6)4 = 0.1127... so slightly over 1/9
9, the elements are: arr[0], arr[1], ... arr[9]
ARR = Average Room Revenue
How to caculated arr at front office
If the calculated ARR is greater that the predetermined ARR then accept the project. otherwise reject the project
formula for arr- total room revenue ARR= ------------------------------ total occupied room
Implement these methods: public static int smallest(int[] arr) { int small = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] < small) small = arr[i]; return small; } public static int largest(int[] arr) { int large = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] > large) large = arr[i]; return large; }
# include<stdio.h> # include<conio.h> void main() { int arr[10]; int i,j,temp; clrscr(); for(i=0;i<10;i++) scanf("%d",&arr[i]); for(i=0;i<9;i++) { for(j=i+1;j<10;j++) { if(arr[i]<arr[j]) { temp=arr[i]; arr[i]=arr[j]; arr[j]=temp; } } } printf("\nSorted array elements :\n"); for(i=0;i<10;i++) printf("%d ",arr[i]) ; getch(); }