Jupiter's gravity is approximately 24.79 m/s² at its equator and 24.92 m/s² at its poles. This is about 2.5 times the gravity on Earth.
The factor of gravity responsible for causing objects to change velocity at a rate of 9.8 ms^2 as they move towards Earth is the acceleration due to gravity. This acceleration is constant near the surface of the Earth and is denoted by 'g'.
acceleration
Gravitational acceleration. It is actually 9.80665 m/s² (acccording to wikipedia). This means that, as a body falls freely under gravity on Earth, it will be accelerating constantly at a rate of 9.80665 m/s².
The acceleration of the car can be calculated using the formula: acceleration = (change in velocity) / time. In this case, the change in velocity is 40 m/s and the time is 80 seconds. Therefore, acceleration = 40 m/s / 80 s = 0.5 m/s². So, the correct answer is A. 0.5 m/s².
9.8 m/s^2 is the acceleration due to gravity on Earth. This value represents the rate at which an object's velocity changes as it falls in a vacuum near the Earth's surface.
5,400
9.81 m/s2 is the acceleration of an object in free fall, responding only to gravity with no other forces on it, on or near the Earth's surface ... otherwise known as the acceleration of gravity. It's always true on or near the surface of the Earth ... if you can provide those conditions: No other forces except gravity acting on the falling object, including no air resistance !
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5,400 N.
The condition would be if the inclined plane is frictionless and the body is subject only to the force of gravity. In this case, the acceleration of the body down the incline would be equal to the acceleration due to gravity, which is approximately 9.8 m/s^2. If the acceleration is given as 4.9 m/s^2, it implies that there is a net force acting on the body causing it to accelerate at that rate.
Weight in a certain place = (mass of the object) x (acceleration of gravity in that place)Weight of that rock, on Earth = (15 kg) x (9.8 meters/sec2) = 147 newtons