Depends on the hotel. I did this job for 2 years (front desk clerk, moved up to supervisor after 5 months). I had minimal training prior to starting. Usually you will be given a day or two to practice on a dummy training program. You must be quick on a computer, know the system well, and above all, BE GOOD TO EXCELLENT WITH PEOPLE. That part is not trainable. This was perhaps the most challenging job I ever had. You must be able to defuse angry persons, sooth those who are unhappy with their stay, and deal well with emergencies (fire drills or real fires, medical issues, strange persons in the lobby, etc...) One of my peers had a guest die on her shift. You also get some very nice people that just want to rest and relax, and those persons are a joy. It is challenging work, but if you are at all interested in the hospitality industry, it is the best place to start...gives you a good perspective.
here are the hotels that are usually included in vacation packages. Note the listings are for downtown and other areas - http://www.southwestvacations.com/hotels/mainHotel.asp?Dest=RNO
The acronym DEST can mean many things. A few of the meanings are Department of Education, Science, and Training; Domestic Emergency Support Team; and Directed Energy Science and Technology.
DEST was created in 1938.
A front desk agent, or receptionist, is an employee in an administrative support position. The employee is usually stationed in a lobby or a front office desk of an organization.
char* u_strcpy (char* dest, const char* src) { char* temp = dest; while ((*dest++ = *src++) != '\0'); return temp; }
As of July 2014, the market cap for Destination Maternity Corporation (DEST) is $315,363,877.14.
Ray ray
mystrcpy (char* dest, char* src) { while ((*dest++ = *src++) != '\0); }
Redirection"DEST", the destination command.
pencil
They do different things, so they are uncomparable.PS: strcpy can be implemented with strlen+memcpy:char *strcpy (char *dest, const char *src){size_t len;len= strlen (src);memcpy (dest, src, len);return dest;}
These should work, if used correctly. // stores srcL + srcR into dest // NOTE: dest must be at least as large as srcL + srcR void strConcat(const char* srcL, const char* srcR, char* dest) { const int lengthL = strLength(srcL); const int lengthR = strLength(srcR); // copy srcL into front of dest int i; for(i = 0; i < lengthL; ++i) { dest[i] = srcL[i]; } // copy srcR into the rest of dest for(i = 0; i < lengthR; ++i) { dest[lengthL + i] = srcR[i]; } dest[lengthL + i] = '\0'; } // copies characters from src to dest // NOTE: dest must be at least as large as src void strCopy(const char* src, char* dest) { const int length = strLength(src); // copy int i; for(i = 0; i < length; ++i) { dest[i] = src[i]; } } // reverses str and puts the result in buff // NOTE: buff must be at least as large as str void strReverse(const char* str, char* buff) { const int length = strLength(str); // special case for zero-length strings if( length == 0 ) { return; } // reversify int i; for(i = 0; i < length; ++i) { buff[i] = str[length - i - 1]; } buff[i] = '\0'; } // returns the number of characters in str int strLength(const char* str) { int length = 0; // take advantage of the fact that all strings MUST end in a null character while( str[length] != '\0' ) { ++length; } return length; }