The net force in the east-west direction is 0 N as the forces cancel out. In the north direction, the net force is 5 N upwards.
A 10 newton force is approximately 2.25 pounds-force, so the 5 pound force is greater.
The net force on the object would be 5 units in the direction of the stronger force, which is the force applied by the boy. This is because the net force is calculated by subtracting the smaller force (5 units) from the larger force (10 units).
The net force on the object is 5 newtons toward the north.
The net force on the object is 5 newtons toward the north.
The net force on the object will be the difference between the two forces, so the net force will be 5 units. Given that the boy is applying 10 units of force in one direction and the girl is applying 5 units of force in the opposite direction, the net force will be 10 units - 5 units = 5 units.
No because .5 is greater than .45
An object at rest pulled in opposite directions by unequal forces will start to move in the direction of the net force. For example, if I have a chair, and I'm pushing with 10 newtons to the right, and my sister is pushing 5 newtons to the left, the net force is 5 newtons to the right. Therefore, I win, and the chair moves to the right, in the direction of the net force.
net force=mass x acceleration => mass=net force/ acceleration mass= 100/ (5/2) => mass=40
The net force is 2 newtons, calculated by subtracting the smaller force from the larger force. The direction of the net force depends on the direction of the larger force.
The net force is 5 newtons to the left (7 N - 2 N = 5 N).
2 Newtons to the North 7-5=2 Simple math =)