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A 720 ml container holds a mixture of red yellow and white paint in 5 3 12 ratio How much more red paint than yellow is present it the mixture?
Wiki User
∙ 14y ago
First I would add the total number of parts together.
5 + 3 + 12 = 20
Now we know that red is 5/20th of the entire mixture, yellow is 3/20th, and white is 12/20th.
red = 5/20 * 720 ml = 180 ml
yellow = 3/20 * 720 ml = 108 ml
white = 12/20 * 720 = 432 ml
We can double check by adding them up and it should come out to 720 ml.
180 ml + 108 ml + 432 ml = 720 ml
180 ml - 108 ml = 72 ml
There is 72 ml more red paint then yellow paint.
Wiki User
∙ 14y ago
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A 720 ml container holds a mixture of red yellow and white paint in a 5 312 ratio How much more red paint than yellow is present in the mixture?
A 720 ml container holds a mixture of red, yellow, and white paint in a 5 : 3 : 12 ratio. How much more red paint than yellow is present in the mixture?
A 720ml container holds mixture of red yellow white paint in a 5 3 12 ratio how much more red paint that yellow is in the mixture?
A 720 ml container holds a mixture of red, yellow, and white paint in a 5 : 3 : 12 ratio. How much more red paint than yellow is present in the mixture?
If a 720 ml container holds a mixture of red yellow and white paint in a five a three and a twelve ratio how much more red paint than yellow paint is in the mixture?
There are 5 parts red, 3 parts yellow and 12 parts white. Therefore there is a total of 20 parts. The total is 720ml, so each part is 720/20ml = 36ml. So there are 36*5ml of red (180ml) and 36*3ml of yellow (108ml). So there are 180-108 = 72ml more red than yellow.
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A container that holds water.
A 720ml container holds a mixture of red yellow and white paint in a 5 3 12 ratio How much more red paint than yellow paint is in the mixture?
10% or 72 more red than yellow(5+3+12)=20720 / 20 = 365 x 36 =1803 x 36 = 10812 x 36 = 432180 / 720 = 25%108 / 720 = 15%432 / 720 = 60%25% - 15% = 10% or 72 more
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